PHP Code : How to scan a folder for all folders in it and then print their sorted names in numbered list ?

please check out this function:
http://www.bin-co.com/php/scripts/filesystem/ls/

try this

<?php
function showDirect( $pth = '.', $lev = 0 ){
    $ignore = array( 'cgi-bin', '.', '..' );// Directories to ignore
    $dh = @opendir( $pth );
    while( false !== ( $file = readdir( $dh ) ) ){
        if( !in_array( $file, $ignore ) ){
            $spacer = str_repeat( '&nbsp;', ( $lev * 4 ) );
            if( is_dir( "$pth/$file" ) ){
                echo "<strong>$spacer $file</strong><br />";
                showDirect( "$pth/$file", ($lev+1) );            
            } else {
                echo "$spacer $file<br />";            
            }
        }
    }
    closedir( $dh );
}
 
?> 
 
 
Calling the function
 
 
showDirect( "." );// Current directory
 
showDirect( "./this/directory" );// Show "this/directory"

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not working afzz....

it will print the directory contents recursively. the spacer variable needs to be modified to output as a list

check this page

https://www.experts-exchange.com/questions/23485982/How-to-scan-all-directories-and-sub-directories-and-print-their-name-with-numbering-link-to-them.html

still strugling...

cant make numbered list and i also unable to print number of files found in each directory in line under it. Also sorted list.

what i want is...

1. Audio
Files Fould : 5

2. English
Files Fould : 0

3. Audio
Files Fould :8

4. English
Files Fould :1

sorry in alphabatically sorted list

You can use this:

<?php
echo '<ul>';
listFiles('/path/to/my/folder/');
echo '</ul>';
 
function listFiles($dir) {
	$it    = opendir($dir);
	$files = 0;
	$dirs  = array();
	while($f = readdir($it)) {
		if($f == '.' || $f == '..') {
			continue;
		}
		if(is_file($dir.'/'.$f)) {
			$files++;
		} else {
			$dirs[] = $dir.'/'.$f;
		}
	}
	
	echo '<li>'.basename($dir);
	echo '<br />Files Found: '.$files;
	if(count($dirs) > 0) {
		echo '<ul>';
		array_map('listFiles', $dirs);
		echo '</ul>';
	}
	echo '</li>';
}

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Thanks very much