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Out-of-range datetime value

Posted on 2008-06-16
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1,978 Views
Last Modified: 2008-06-18
       
       
      <cfset datepassed = #DATEFORMAT(now(), "dd/mm/yy")#>

        SELECT  CONVERT(VARCHAR(10), TIMEDATE , 120) as varDate
        FROM orders
        WHERE YEAR(TIMEDATE)  = YEAR('#datepassed#')
        AND MONTH(TIMEDATE)  = MONTH('#datepassed#')
        AND DAY(TIMEDATE)  = DAY('#datepassed#')

ERROR:

The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
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Question by:pigmentarts
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8 Comments
 
LVL 24

Expert Comment

by:DBAduck - Ben Miller
ID: 21797913
Whenever you use Datetime, you can either use mm/dd/yyyy or you can use a string of yyyymmdd.

If you are using a machine that has the Regional settings like UK then they will want the dd/mm/yyyy settings, then I would use the universal format yyyymmdd instead.
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Expert Comment

by:DBAduck - Ben Miller
ID: 21797916
And it is DATETIME, not TIMEDATE.
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LVL 51

Expert Comment

by:Mark Wills
ID: 21810433
OK,  the    CONVERT(VARCHAR(10), TIMEDATE , 120)    is using a format number. That number is telling convert how to read/ interpret the variable TIMEDATE. Now if TIMEDATE is a legitimate datetime column, then no problems, it knows how to format. However, when using a string / variable such as datepassed, then it has to understand how it is formatted... So, before you can use datetime functions such as year, month, day, then it has to recognise the string as a date...

By the looks of things, you do not want time as a component, so, probably best to do something like :

SELECT  CONVERT(VARCHAR(10), TIMEDATE , 120) as varDate
FROM orders
WHERE convert(datetime,CONVERT(varchar(20), TIMEDATE , 106))  = convert(datetime,'#datepassed#',103)

basically allowing the datetime to do it's match without the time component, and expressing both fields as a legitimate datetime construct.
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LVL 12

Author Comment

by:pigmentarts
ID: 21810992
thank you for all your help
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Author Comment

by:pigmentarts
ID: 21812932
mark_aills:

using your code i still get this...

Syntax error converting datetime from character string.
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LVL 51

Expert Comment

by:Mark Wills
ID: 21813417
use a 4 digit year in datepassed
0
 
LVL 51

Accepted Solution

by:
Mark Wills earned 500 total points
ID: 21813502
this works : select convert(datetime,'21/01/2008',103)
this fails : select convert(datetime,'21/01/08',103)

this works: select convert(datetime,'21/01/08',03)
this fails : select convert(datetime,'21/01/2008',03)

even though the books online show it as yy, it isn't really... remember how I said it must match - it is really , really fussy....

have a look at the codes below...


Without century (yy)      With century (yyyy)  Standard       Input/Output 
-                         0 or 100             Default        mon dd yyyy hh:miAM (or PM)
1                         101                  U.S.           mm/dd/yyyy
2                         102                  ANSI           yy.mm.dd
3                         103                  British/French dd/mm/yy
4                         104                  German         dd.mm.yy        
5                         105                  Italian        dd-mm-yy
6                         106                  -              dd mon yy
7                         107                  -              Mon dd, yy
8                         108                  -              hh:mm:ss
-                         9 or 109             Default + ms   mon dd yyyy hh:mi:ss:mmmAM (or PM)
10                        110                  USA            mm-dd-yy
11                        111                  JAPAN          yy/mm/dd
12                        112                  ISO            yymmdd
-                         13 or 113            Europe         dd mon yyyy hh:mm:ss:mmm(24h)
14                        114                  -              hh:mi:ss:mmm(24h)
-                         20 or 120            ODBC canonical yyyy-mm-dd hh:mi:ss(24h)
-                         21 or 121            ODBC canonical yyyy-mm-dd hh:mi:ss.mmm(24h)
-                         126                  ISO8601        yyyy-mm-ddThh:mm:ss.mmm (no spaces)
                          127                  ISO8601        yyyy-mm-ddThh:mm:ss.mmmZ   where Z = time zone(no spaces)               
-                         130                  Hijri          dd mon yyyy hh:mi:ss:mmmAM
-                         131                  Hijri          dd/mm/yy hh:mi:ss:mmmAM
 

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LVL 12

Author Comment

by:pigmentarts
ID: 21813602
i see what you mean now. just had to get my head around it. working now thanks
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