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Need to export all jpeg files (blob entries) to filesystem

We have an old Linux box setup years ago as a PHP/MySQL based webserver.  We're upgrading it to a new server, and need to get all the images (jpeg type) that are stored in the sql database out to the filesystem.  I found a PHP script to do just that, but I'm having problems.  I think my problems are that this server is running PHP 4.3.2.  We have no expertise in Linux, or PHP, so we're trying to extract this info without putting effort into upgrading the system first.  I know this has got to be a simple thing to do.  Any ideas?  Oh, the way it's to name the file, is to take and combine the info in 2 of the fields in the table, and append .jpg on the end of it.

I have attached my code.  What's happing when I run it, is that it appears to be bypassing the PHP engine because it simply shows me the PHP code in my browser.  I've tested PHP with the phpinfo() function and that works fine.

Thanks for your help.
< ?php
$location="/var/www/website.com/html/imagearchive/";
 
$db = mysql_pconnect("localhost");
mysql_select_db("database",$db);
 
$sql="select person.name, media.id, media.data from media LEFT JOIN person ON (person.id=media.l_table_name_id)";
 
$rs = mysql_query($sql,$db);
 
echo "<h2>EXPORTING INTO $location</h2>";
$counter=0;
while ($row=mysql_fetch_object($rs)) {
$filename=$location.$row->person.name"."media.id..jpg;
$file=fopen($filename,w');
if (fwrite($file,$row->image)) {
echo $filename.<br />;
$counter++;
}
}
 
echo <h2>$counter images exported</h2>;
? >

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ResortCompanies
Asked:
ResortCompanies
1 Solution
 
qaelanCommented:
You might try removing the spaces between

< ?php

and

? > 

At the start and end of the file. They should be <?php and ?>, respectively
0
 
Matthew KellyCommented:
Try this code. The php being output to the screen is caused by the space between the ? and the > sign at the start and end.

There are also a few php syntax errors, which I corrected below.

Let me know if I did not code it right.


<?php
$location="/var/www/website.com/html/imagearchive/";
 
$db = mysql_pconnect("localhost");
mysql_select_db("database",$db);
 
$sql="select person.name, media.id, media.data from media LEFT JOIN person ON (person.id=media.l_table_name_id)";
$rs = mysql_query($sql,$db);
 
echo "<h2>EXPORTING INTO ".$location."</h2>";
 
if ( $rs && mysql_num_rows($rs) > 0 )
{
	$counter=0;
	for ( $i=0; $i < mysql_num_rows($rs); $i++ )
	{
		$name = mysql_result($result,$i,0);
		$id = mysql_result($result,$i,1);
		$data = mysql_result($result,$i,2);
		$filename = $location.$name.$id.".jpg";
		$file=fopen($filename,'w');
		if (fwrite($file,$data)) 
		{
			echo $filename."<br />";
			$counter++;
		}
	}
}
else
{
echo "No files found";
}
 
echo "<h2>".$counter." images exported</h2>";
?>

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fiboCommented:
Some typos and errors with ' and ".
Code is easier to grasp and debug when indented.

If doing lots of development, you shoud consider using commercial PHP IDEs like Zend or NuCoder: they would help you spotting at once these typos.
They offer trial versions that you can use for free for 2 or 4 weeks: this will help you to determine if the time you save is worth the money. They both have a "personal" version at $100-120.

<?php
$location="/var/www/website.com/html/imagearchive/";
 
$db = mysql_pconnect("localhost");
mysql_select_db("database",$db);
 
$sql="select person.name as my_name, media.id as my_id, media.data as my_data 
from media LEFT JOIN person ON (person.id=media.l_table_name_id)";
 
$rs = mysql_query($sql,$db);
 
echo "<h2>EXPORTING INTO $location</h2>";
$counter=0;
while ($row=mysql_fetch_object($rs)) {
  $filename=$location.$row->my_name . '.' . $row->my_id . '.jpg';
  echo "$filename :";
  $file=fopen($filename,'w');
  if (fwrite($file,$row->my_data)) {
    echo "OK<br />";
    $counter++;
  } else echo 'fail **<br>';
}
 
echo "<h2>$counter images exported</h2>";
?>

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ResortCompaniesAuthor Commented:
Thanks, worked like a charm.
0
 
fiboCommented:
Glad it worked, thx for the points
0

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