[Webinar] Streamline your web hosting managementRegister Today

x
?
Solved

Unzip only files from zip file.. junk the paths

Posted on 2008-06-17
7
Medium Priority
?
640 Views
Last Modified: 2012-06-27
Hi,

I have some code using Archive::Zip that will extract the data from a zip file into a destination folder. I'm not able to work out how not to keep the directory structure of the zip and only extract the files.

I would like to do something simulart to

unzip -o -j /zipfile.zip

I am not able to get Archive::Zip to junk the paths in the zip file.

Thanks

Steve
0
Comment
Question by:APNFSSC
  • 3
  • 3
7 Comments
 
LVL 9

Expert Comment

by:Suhas .
ID: 21801870
Hello Steve,
you can use system("unzip \-o \-j \/zipfile\.zip");

Regards,
suhasbharadwaj
0
 
LVL 39

Expert Comment

by:Adam314
ID: 21803247
You could use the extractMemberWithoutPaths function.  What are you doing now?
0
 
LVL 10

Author Comment

by:APNFSSC
ID: 21808192
Hi,

Thanks for the replies.

Here is what I have now which works thanks suhasbharadwaj.

I would prefer not to break out to a shell to perform this operation so I'm leaving this item open for 1 more day to see if extractMemberWithoutPaths is possible.

I had a go at it and could not get it working with extractMemberWithoutPaths but if someone can provide a code snippit that would be great.

Thanks

Steve
sub unzip_this_junk_paths{
        my ($zipfile, $destination, $error_path) = @_;
        my $zip = Archive::Zip->new();
        unless ( $zip->read( "$zipfile" ) == AZ_OK ) {
            move("$zipfile", "$error_path/.") and die;
    }
        system("unzip \-o \-j \-qq $zipfile -d $destination");
}

Open in new window

0
Get your problem seen by more experts

Be seen. Boost your question’s priority for more expert views and faster solutions

 
LVL 39

Expert Comment

by:Adam314
ID: 21808419

use Archive::Zip;
 
my $zip = Archive::Zip->new( 'test1.zip' );
$zip->extractMemberWithoutPaths($_) foreach ($zip->members);

Open in new window

0
 
LVL 10

Author Comment

by:APNFSSC
ID: 21808441
Is it possible to pass the destination using this method?
0
 
LVL 10

Author Comment

by:APNFSSC
ID: 21808457
also will this overwrite existing files without failing which is what the -o is doing in the system call
0
 
LVL 39

Accepted Solution

by:
Adam314 earned 500 total points
ID: 21813293
Files will be overwritten.  To change the output directory, use chdir before extracting.  Use either a relative or full path to the zip file.
chdir('zipout') or die "chdir: $!\n";
my $zip = Archive::Zip->new();
($zip->read('../test1.zip')==AZ_OK) or die "Read error\n";
$zip->extractMemberWithoutPaths($_) foreach ($zip->members);

Open in new window

0

Featured Post

Take Control of Web Hosting For Your Clients

As a web developer or IT admin, successfully managing multiple client accounts can be challenging. In this webinar we will look at the tools provided by Media Temple and Plesk to make managing your clients’ hosting easier.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I've just discovered very important differences between Windows an Unix formats in Perl,at least 5.xx.. MOST IMPORTANT: Use Unix file format while saving Your script. otherwise it will have ^M s or smth likely weird in the EOL, Then DO NOT use m…
Checking the Alert Log in AWS RDS Oracle can be a pain through their user interface.  I made a script to download the Alert Log, look for errors, and email me the trace files.  In this article I'll describe what I did and share my script.
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…
Six Sigma Control Plans
Suggested Courses

612 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question