We value your feedback.
Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!
Course Of The Month
4 days, 9 hours left to enrollBecome a Premium Member and unlock a new, free course in leading technologies each month.
Solved
Creating a new ID in VBA
Posted on 2008-06-17
Hello,
I'm trying to create a new ID for any additional records we add into our database. I started out by creating an entry form that (all unbound text boxes) with 2 buttons one which I will append the fields to the table and one to fetch the current max id +1 for this record. the ID button is not working and I've tried different variations. We have 2 tables one which permanent and is a SQL table (linked to MS SQL) and the other a temprary table, both of which have IDs. I'm trying to pull that max number ID and 1 to it and assign it to a variable where I can send the value to a text box on the form. below is my code, what am I doing wrong?
I'm trying to create a new ID for any additional records we add into our database. I started out by creating an entry form that (all unbound text boxes) with 2 buttons one which I will append the fields to the table and one to fetch the current max id +1 for this record. the ID button is not working and I've tried different variations. We have 2 tables one which permanent and is a SQL table (linked to MS SQL) and the other a temprary table, both of which have IDs. I'm trying to pull that max number ID and 1 to it and assign it to a variable where I can send the value to a text box on the form. below is my code, what am I doing wrong?
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
Set rst = CurrentDb.OpenRecordset("SELECT Max(tblPhysContactInfo.ID)+1 AS [NewPID] FROM tblPhysContactInfo;")
If Not rst.EOF Then
rst.MoveFirst
intPID = rst![NewPID]
End If
Case 2
Set rst = CurrentDb.OpenRecordset("SELECT IIf(Max([tblTempContactInfo].[ID])+1=1,'2000001',Max([tblTempContactInfo].[ID])+1) AS [NewPID] FROM tblTempContactInfo;")
If Not rst.EOF Then
rst.MoveFirst
intPID = rst![NewPID]
End If
End Select
Me.txtPID.Value = intPID
End Sub
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
3-
2
6 Comments
Why not set the ID column your tables to automatically increment?
Use the IDENTITY keyword in SQL Server.
Use the IDENTITY keyword in SQL Server.
Active 1 day ago
try this
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblPhysContactInfo"), 0) + 1
Case 2
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblTempContactInfo"), 0) + 1
End Select
Me.txtPID.Value = intPID
End Sub
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblPhysContactInfo"), 0) + 1
Case 2
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblTempContactInfo"), 0) + 1
End Select
Me.txtPID.Value = intPID
End Sub
Active 1 day ago
that is, if your db application is a single user, for multiuser you will used @@identity
Thanks capricorn1, but when I clicked the button it gave me a Run-time error '6': Overflow
and it takes me to line 21 or 31 based on my selection.
Any ideas?
and it takes me to line 21 or 31 based on my selection.
Any ideas?
Featured Post
Join Percona’s Senior Technical Services Engineer, Adamo Tonete as he presents “MongoDB Index Types, How, When and Where Should They be Used?” on Wednesday, July 12, 2017 at 11:00 am PDT / 2:00 pm EDT (UTC-7).
Question has a verified solution.
If you are experiencing a similar issue, please ask a related question
In this blog post, we’ll look at how ClickHouse performs in a general analytical workload using the star schema benchmark test.
If you need a simple but flexible process for maintaining an audit trail of who created, edited, or deleted data from a table, or multiple tables, and you can do all of your work from within a form, this simple Audit Log will work for you.
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…
Do you want to know how to make a graph with Microsoft Access? First, create a query with the data for the chart. Then make a blank form and add a chart control. This video also shows how to change what data is displayed on the graph as well as form…
Suggested Courses
Course of the Month4 days, 9 hours left to enroll
690 members asked questions and received personalized solutions in the past 7 days.
Join the community of 500,000 technology professionals and ask your questions.