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Creating a new ID in VBA
Posted on 2008-06-17
Hello,
I'm trying to create a new ID for any additional records we add into our database. I started out by creating an entry form that (all unbound text boxes) with 2 buttons one which I will append the fields to the table and one to fetch the current max id +1 for this record. the ID button is not working and I've tried different variations. We have 2 tables one which permanent and is a SQL table (linked to MS SQL) and the other a temprary table, both of which have IDs. I'm trying to pull that max number ID and 1 to it and assign it to a variable where I can send the value to a text box on the form. below is my code, what am I doing wrong?
I'm trying to create a new ID for any additional records we add into our database. I started out by creating an entry form that (all unbound text boxes) with 2 buttons one which I will append the fields to the table and one to fetch the current max id +1 for this record. the ID button is not working and I've tried different variations. We have 2 tables one which permanent and is a SQL table (linked to MS SQL) and the other a temprary table, both of which have IDs. I'm trying to pull that max number ID and 1 to it and assign it to a variable where I can send the value to a text box on the form. below is my code, what am I doing wrong?
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
Set rst = CurrentDb.OpenRecordset("SELECT Max(tblPhysContactInfo.ID)+1 AS [NewPID] FROM tblPhysContactInfo;")
If Not rst.EOF Then
rst.MoveFirst
intPID = rst![NewPID]
End If
Case 2
Set rst = CurrentDb.OpenRecordset("SELECT IIf(Max([tblTempContactInfo].[ID])+1=1,'2000001',Max([tblTempContactInfo].[ID])+1) AS [NewPID] FROM tblTempContactInfo;")
If Not rst.EOF Then
rst.MoveFirst
intPID = rst![NewPID]
End If
End Select
Me.txtPID.Value = intPID
End Sub
[X]
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6 Comments
Why not set the ID column your tables to automatically increment?
Use the IDENTITY keyword in SQL Server.
Use the IDENTITY keyword in SQL Server.
Active today
try this
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblPhysContactInfo"), 0) + 1
Case 2
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblTempContactInfo"), 0) + 1
End Select
Me.txtPID.Value = intPID
End Sub
Private Sub cmdGetNewID_Click()
'Get new ID for respondent
Dim intPID As Integer
Dim db As Database
Dim rst As Recordset
Set db = CurrentDb()
'check which contact type it will be
'If radio button 1 is selected then Phys table (Permanent)
'If radio button 2 is selected then Temp table (Temprary)
Select Case Me.frmContactType.Value
Case 1
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblPhysContactInfo"), 0) + 1
Case 2
' Set rst = CurrentDb.OpenRecordset("S
' If Not rst.EOF Then
' rst.MoveFirst
' intPID = rst![NewPID]
' End If
intPID = Nz(DMax("ID", "tblTempContactInfo"), 0) + 1
End Select
Me.txtPID.Value = intPID
End Sub
Active today
that is, if your db application is a single user, for multiuser you will used @@identity
Thanks capricorn1, but when I clicked the button it gave me a Run-time error '6': Overflow
and it takes me to line 21 or 31 based on my selection.
Any ideas?
and it takes me to line 21 or 31 based on my selection.
Any ideas?
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