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MySQL Query Syntax

Posted on 2008-06-18
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Last Modified: 2013-12-12
I have the following query:

SELECT a.venuename, a.venueid, b.stars, b.reviewtext, AVG( stars ) AS average, sum(b.total) AS total
FROM venue a, venuereview b
WHERE a.venueid = b.venueid
AND b.id = 50
AND b.switch = '1'
GROUP BY b.venueid
ORDER BY average DESC


What I want to do is display the review with the ID of 50 first, then display the rest of the reviews for the venueid related to the id - 50.

Can anyone help me out?
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Comment
Question by:lvollmer
  • 2
  • 2
4 Comments
 
LVL 142

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 21815562
if I understand correctly:
SELECT a.venuename, a.venueid, b.stars, b.reviewtext, b.id, AVG( stars ) AS average, sum(b.total) AS total
FROM venue a, venuereview b
WHERE a.venueid = b.venueid
AND b.switch = '1'
GROUP BY b.venueid
ORDER BY CASE WHEN b.id = 50 THEN 0 ELSE 1 END ASC, average DESC

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0
 

Author Comment

by:lvollmer
ID: 21815744
Angel - that gave me all reviews.

here is an example of what I need.

reviewID-50 has a venueID of 900

venueID900 has 4 reviews

I want to display those 4 reviews, with the first review displaying reviewID-50
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LVL 142

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 21815775
so, when a VenueID has at least 1 reviewID = 50, then show them all for that VenueID
SELECT a.venuename, a.venueid, b.stars, b.reviewtext, b.id, AVG( stars ) AS average, sum(b.total) AS total

FROM venue a

JOIN venuereview b

  ON a.venueid = b.venueid

 AND b.switch = '1'

WHERE exists ( SELECT NULL 

                 FROM venuereview i

                WHERE a.venueid = i.venueid

                  AND i.id = 50

             )

GROUP BY b.venueid

ORDER BY CASE WHEN b.id = 50 THEN 0 ELSE 1 END ASC, average DESC

Open in new window

0
 

Author Comment

by:lvollmer
ID: 21815877
slight modification and it works - thanks!

SELECT a.venuename, a.venueid, b.stars, b.reviewtext, b.id, AVG( stars ) AS average, sum( b.total ) AS total
FROM venue a
JOIN venuereview b ON a.venueid = b.venueid
AND b.switch = '1'
WHERE EXISTS (

SELECT NULL
FROM venuereview i
WHERE a.venueid = i.venueid
AND i.id =49
)
GROUP BY b.id
ORDER BY CASE WHEN b.id =49
THEN 0
ELSE 1
END ASC , average DESC
0

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