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MySQL Query Syntax

I have the following query:

SELECT a.venuename, a.venueid, b.stars, b.reviewtext, AVG( stars ) AS average, sum(b.total) AS total
FROM venue a, venuereview b
WHERE a.venueid = b.venueid
AND b.id = 50
AND b.switch = '1'
GROUP BY b.venueid
ORDER BY average DESC

What I want to do is display the review with the ID of 50 first, then display the rest of the reviews for the venueid related to the id - 50.

Can anyone help me out?

Guy Hengel [angelIII / a3]

if I understand correctly:

SELECT a.venuename, a.venueid, b.stars, b.reviewtext, b.id, AVG( stars ) AS average, sum(b.total) AS total
FROM venue a, venuereview b
WHERE a.venueid = b.venueid
AND b.switch = '1'
GROUP BY b.venueid
ORDER BY CASE WHEN b.id = 50 THEN 0 ELSE 1 END ASC, average DESC

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Larry Vollmer

ASKER

Angel - that gave me all reviews.

here is an example of what I need.

reviewID-50 has a venueID of 900

venueID900 has 4 reviews

I want to display those 4 reviews, with the first review displaying reviewID-50

ASKER CERTIFIED SOLUTION

Guy Hengel [angelIII / a3]

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Larry Vollmer

ASKER

slight modification and it works - thanks!

SELECT a.venuename, a.venueid, b.stars, b.reviewtext, b.id, AVG( stars ) AS average, sum( b.total ) AS total
FROM venue a
JOIN venuereview b ON a.venueid = b.venueid
AND b.switch = '1'
WHERE EXISTS (

SELECT NULL
FROM venuereview i
WHERE a.venueid = i.venueid
AND i.id =49
)
GROUP BY b.id
ORDER BY CASE WHEN b.id =49
THEN 0
ELSE 1
END ASC , average DESC