Scott Pletcher
asked on
Calculate length of tarp needed to extend 12 linear feet (at 0 degrees), but sloping at 25 degrees instead
I need to cover an area with a tarp, but sloping downward to allow rain to run off.
The area to be covered is 12 feet long (ground/linear measurement).
The tarp will start 9 feet above the ground and slope downward at roughly a 25 degree angle.
How much length of tarp will I need to cover the 12 linear feet after adjusting for the slope?
|*tarp starts here, 9 feet up
|**angled down at ~25 degrees
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|_________________________ _________1 2 feet of concrete, end of area to be covered
Would be great if you could include the formula too :-) .
The area to be covered is 12 feet long (ground/linear measurement).
The tarp will start 9 feet above the ground and slope downward at roughly a 25 degree angle.
How much length of tarp will I need to cover the 12 linear feet after adjusting for the slope?
|*tarp starts here, 9 feet up
|**angled down at ~25 degrees
|
|
|
|
|
|
|_________________________
Would be great if you could include the formula too :-) .
The angle is the arctan( 9/12) = 36.8 degrees.
ASKER
But I dont want the tarp to come down to the ground ... only as far down as it would go at roughly 22-25 degrees.
So it won't form a triangle -- it will be an open-ended rectangle.
That is, where the tarp ends up after sloping down should still be some feet off the ground, not at ground level.
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| |--<<-- tarp ends here
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__________________________ _________
I can tie the tarp to the middle of the pole, it doesn't hv to reach all the way to the ground.
So it won't form a triangle -- it will be an open-ended rectangle.
That is, where the tarp ends up after sloping down should still be some feet off the ground, not at ground level.
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| |--<<-- tarp ends here
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|
__________________________
I can tie the tarp to the middle of the pole, it doesn't hv to reach all the way to the ground.
If you hold the angle to 25 degrees, the vertical side of the triangle will be
12 ft * tan(25) = 12 * 0.466 = 5.66 ft ==> 9 - 5.66 = 3.34 ft gap
The length of the tarp will be
12 ft / cos(25) = 12 / 0.906 = 13.24 ft
12 ft * tan(25) = 12 * 0.466 = 5.66 ft ==> 9 - 5.66 = 3.34 ft gap
The length of the tarp will be
12 ft / cos(25) = 12 / 0.906 = 13.24 ft
ASKER
Thank you so much!!
ASKER CERTIFIED SOLUTION
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ASKER
Sorry, your proposed solution to me just didn't hold up as accurate :-( .
>> ScottPletcher please recheck you calculator!!!
cos( 25 degrees) does equal 0.906
cos( 25 radians) is 0.9912
25 radians means you go around a circle almost exactly four time.
The effective angle is -1.2 degrees.
cos( 25 degrees) does equal 0.906
cos( 25 radians) is 0.9912
25 radians means you go around a circle almost exactly four time.
The effective angle is -1.2 degrees.
Where is this calculator website??
And what did it give for an answer??
Was it actually different from the one I gave??
And what did it give for an answer??
Was it actually different from the one I gave??
ASKER
Oops, you are quite right as to the COS().
However, I still think the overall formula and result are wrong.
The side being determined is the hypotenuse. If one side is 12 ft and the other is 3.34 ft, the hypotenuse should be sqrt(12^^^^2 + 3.34^^^^2) which is 12.46 (even I know sqrt of (a^2 + b^2) :-) ).
I can't find any calculation that yields a tarp length of over 13 ft with a linear distance of 12 ft and an angle less than or equal to 25 degrees.
Perhaps you can correct me:
linear distance (12 ft)
-------------------------- ---------- ---------- ---------- ------
---<<--25 degree angle
--tarp
--------extending
-------------------at 25 degrees
-------------------------- ---------f orming a right triangle with the upper edge of the concrete
However, I still think the overall formula and result are wrong.
The side being determined is the hypotenuse. If one side is 12 ft and the other is 3.34 ft, the hypotenuse should be sqrt(12^^^^2 + 3.34^^^^2) which is 12.46 (even I know sqrt of (a^2 + b^2) :-) ).
I can't find any calculation that yields a tarp length of over 13 ft with a linear distance of 12 ft and an angle less than or equal to 25 degrees.
Perhaps you can correct me:
linear distance (12 ft)
--------------------------
---<<--25 degree angle
--tarp
--------extending
-------------------at 25 degrees
--------------------------
The gap between the end of the tarp and the ground is 3.34 feet.
This is not part of the triangle.
The sides of the triangle are 12 and 5.66
sqrt(12² + 5.66²) = sqrt(144 + 32.04) = sqrt(176.04) = 13.24 feet.
This is not part of the triangle.
The sides of the triangle are 12 and 5.66
sqrt(12² + 5.66²) = sqrt(144 + 32.04) = sqrt(176.04) = 13.24 feet.
ASKER
Yep, that makes more sense.
Sorry about that, I need to get the q re-opened and then assign you the pts.
I've already ordered the tarp, will probably have to cut down the angle to make it cover all the way :-) .
Sorry about that, I need to get the q re-opened and then assign you the pts.
I've already ordered the tarp, will probably have to cut down the angle to make it cover all the way :-) .
No problem.
A little more to allow for some sag.