SQL Statement to count entries for each day of the month

declare @StartDate datetime, @Begin datetime, @End datetime
set @startdate = getdate()  --date doesn't matter here.

set @Begin = cast(cast(month(getdate()) as varchar(2)) + '/1/' + cast(year(getdate()) as varchar(4)) as datetime)
set @end = dateadd(m, 1, @Begin)

select datepart(d, datefield), count(*)
from yourtable
where datefield >= @Begin And
DateField < @End
group by datepart(d, datefield)
order by 1 desc

Thanks for the post. I modifed the statment to work with my db

There seems to be 3 problems. @StartDate and @StartDateNext are getting their values in the code. I need them to be supplied. It also seems to be counting only the StartDate if it lands on the day. If someones start date is 5/1 and end date is 5/3 they would be included in the count for Day 1, 2, and 3. Right now they are only being included in the count for Day 1. Also the Days are only going from day 1 to 19.

Thanks.

Declare @Start datetime, @StartDate datetime, @StartDateNext datetime
 
set @Start = getdate()  --date doesn't matter here.
 
set @StartDate = cast(cast(month(getdate()) as varchar(2)) + '/1/' + cast(year(getdate()) as varchar(4)) as datetime)
set @StartDateNext = dateadd(m, 1, @StartDate)
 
SELECT     DATEPART(d, StartDate) AS Day, COUNT(*) AS Count
FROM         dbo.Guests
WHERE     (StartDate >= @StartDate) AND (StartDate < @StartDateNext)
GROUP BY DATEPART(d, StartDate)

Select allOpen in new window

I was able to modify it so I can supply the date and it is showing all the days of the month.

Now I just need the count.

Declare @Start datetime
 
 
set @Start = getdate()  --date doesn't matter here.
 
 
SELECT     DATEPART(d, StartDate) AS Day, COUNT(*) AS Count
FROM         dbo.BookingNbrs
WHERE     (StartDate >= @StartDate) AND (StartDate < @StartDateNext)
GROUP BY DATEPART(d, StartDate)

Select allOpen in new window

Not sure what you mean...it should give you the count.  Am I missing something?

The count is not correct. Plus if no one has a date on the 5/1/2008 for example, it doesnt show day 2.
lets say this is the table
ID      StartDate          EndDate
1       05/3/2008       05/12/2008
2       05/10/2008       05/20/2008
3       05/19/2008       Null

this is what I am getting now.
Day Count
3         1
10       1
19       1

It is saying only 1 guy has a start day of the 3rd, 1 on the 10th, and 1 on the 19th.

The out put should be
Day Count
1      0         //No Guests
2      0         //No Guests
3      1         //ID 1 arrives
4      1
5      1
6      1
7      1
8      1
9      1           //ID 1 was the only guest the 1st throught the 9th
10    2           //ID 1 is still a guest and ID 2 arrived.
11    2          
12    2
13    1           //ID 1 left on the 12th so he won't be included on the 13th
14    1
15    1
16    1
17    1          
18    1
19    2           //ID 2 is still a guest and ID 3 arrives.
20    1           //ID 2 left on the 19th so he won't be included on the 20th
21    1
22    1
23    1
24    1
25    1
26    1
27    1
28    1
29    1
30    1           //if the month only has 30 days it would stop here.
31    1              

Ahhh...thats a different monster entirely....I can't really see a set-based solution for this.  Some looping is going to be required.

This can be written (optimized) to be without cycle, however for that case you need prepared temp table of consequent numbers from 1 to 31, which require cycle though :)

If you wish, I will write this variant.

Thanks for the post. That worked great!