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pattern match in shell script

Posted on 2008-06-19
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Last Modified: 2013-12-26
How do I pattern match DL_XXX in a shell script. I want to ignore directories starting with DL

can I do somethign like

$dirName != "DL%"
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Question by:saibsk
6 Comments
 
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by:amit_g
ID: 21826895
Depends on what exactly you are doing. You could do something like this

echo !(DL_*)
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Accepted Solution

by:
ozo earned 500 total points
ID: 21826939
if [[  "$dirName" ==  DL*  ]] ; then echo ignore ; fi
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Expert Comment

by:Tintin
ID: 21826942
Can you show us some context?

If think you might be after something like:


if echo $dirNAME | grep "DL_???" >/dev/null
then
   echo "Matches"
else
   echo "Does not match"
fi

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Expert Comment

by:ghostdog74
ID: 21827392
use find
find /path -type f -name "DL*" -print | while read file
do
 # do something to file
done

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by:omarfarid
ID: 21828604
you may try

 ls | grep -v DL_...*
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Expert Comment

by:Tintin
ID: 21828687
Well, certainly lots of wild guesses as to what you really mean.  Hopefully you'll get back to us with some more detail.
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