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What value does $query = mysql_query("select * from member where loginID like '$loginID'") return if there is no field with loginID = $loginID

Posted on 2008-06-21
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Last Modified: 2008-06-22
I have the following code...
$query = mysql_query("select * from member where loginID like '$loginID'");

I have an if statement that follows as thus...
if(!empty($query)){
//code
}

that if statement, though, won't execute if there is a value in $query
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Question by:jabrthel
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4 Comments
 
LVL 82

Accepted Solution

by:
hielo earned 2000 total points
ID: 21839741
it returns a resource which has zero records. So if you are trying to find out how many records were returned you need:
$query = mysql_query("select * from member where loginID like '$loginID'");
if( 0==mysql_num_rows($query) )
{
  echo "No records found";
}
0
 

Author Comment

by:jabrthel
ID: 21839807
That worked, I just needed to change == to !=
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Author Comment

by:jabrthel
ID: 21839809
thanks
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LVL 82

Expert Comment

by:hielo
ID: 21840973
You are welcome!
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