Solved

AJAX Problem continuation

Posted on 2008-06-23
5
261 Views
Last Modified: 2010-04-21
Hello,


I used the exact same ajax code(http://www.experts-exchange.com/Programming/Languages/Scripting/AJAX/Q_23504279.html) at my job and it works fine except that after I enter in my comments and click "Update" the comment does not appear.  I have to hit refresh to see my changes.  I have been struggling with it all morning.
var xmlHttp=null; 
 
 function editComment(id) 
{ 
	xmlHttp=GetXmlHttpObject(); //See if it works with users browser. 
	if (xmlHttp==null) 
	{ 
		alert ("Browser does not support HTTP Request"); 
		return false; 
	} 
  xmlHttp.onreadystatechange=function(){stateChanged(id);}
	var url="schedAjax.asp"; 
	var data = "edtShed=Yes&cm_id="+id+"&cmt="+encodeURIComponent( document.getElementById("cmt"+id).value ); 
	xmlHttp.open("POST",url,true); 
	xmlHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 
	xmlHttp.setRequestHeader("Content-length", data.length); 
  xmlHttp.send( data ); 
}
 
 
function stateChanged(id) 
{ 
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
 { 
 document.getElementById("showCmt"+id).innerHTML=xmlHttp.responseText 
 hideEdit(id);
 } 
}
 
 
function GetXmlHttpObject()
{
var xmlHttp=null;
try
  {
  // Firefox, Opera 8.0+, Safari
  xmlHttp=new XMLHttpRequest();
  }
catch (e)
  {
  // Internet Explorer
  try
    {
    xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
    }
  catch (e)
    {
    try
      {
      xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
      }
    catch (e)
      {
      alert("Your browser does not support AJAX!");
      return false;
      }
    }
  }
 
  return xmlHttp;
}
 
 function show(id)
 {
 	document.getElementById(id).style.display="";
 }
 function hide(id)
 {
 	document.getElementById(id).style.display="none";
 }
 
 function showEdit(id)
 {
		show('cmt'+id);
    show('Update'+id);
    hide('Edit'+id);
    hide('showCmt'+id);
 }
 function hideEdit(id)
 {
		hide('cmt'+id);
    hide('Update'+id);
    show('Edit'+id);
    show('showCmt'+id);
 }
 
 
<!------------------------------------------------------------------------------------------------------------->            
<DIV>                     
<TABLE>
CODE.....
 
           <%
	           Set rs=Server.CreateObject("ADODB.Recordset") 
	           sSQL = "SELECT * FROM misComment WHERE ID = " & CLng(d) & " ORDER BY vDATE DESC"
	           rs.Open sSQL, objConn
	           do while not rs.EOF
           %>
             
             <form>
             <tr>
               <td width="10%"><%=rs("vdate")%></td>
               <td width="10%"><%=rs("usr")%></td>    
               <td>
               	<span id="showCmt<%=rs("id")%>">
               		<%=rs("comment")%>
               	</span>
               		<textarea style="display:none" id="cmt<%=rs("id")%>" cols="50" rows="5"><%=rs("comment")%></textarea>
               </td>
					     <td>
					     		<input type="button" id="Edit<%=rs("id")%>" value="Edit" onclick="showEdit('<%=rs("id")%>')"  name="edit" />
					     		<input type="button" value="Update" name="edit" id="Update<%=rs("id")%>" style="display:none;" onclick="editComment('<%=rs("id")%>')"  /></td>
             </tr>
             </form>
             
             <%
					    rs.MoveNext
			    		Loop
    				 %>
 
MORE CODE-----
</TABLE>
</DIV>
<!------------------------------------------------------------------------------------------------------------->

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Question by:Isaac
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5 Comments
 
LVL 82

Accepted Solution

by:
hielo earned 500 total points
ID: 21847618
You are sending the edits to schedAjax.asp. schedAjax.asp MUST echo back the comment.  So, the last statement in schedAjax.asp
should be:
Response.Write( Request("cmt") )
0
 
LVL 5

Author Comment

by:Isaac
ID: 21848369
Hielo,

You are a life saver.  Thanks!!!
0
 
LVL 5

Author Closing Comment

by:Isaac
ID: 31469802
Hielo is excellent at AJAX.
Your code and explanations make sense.
Thanks.
0
 
LVL 82

Expert Comment

by:hielo
ID: 21848423
You are welcome!
0
 
LVL 5

Author Comment

by:Isaac
ID: 23185233
Hello Hielo,

I hope all is well.  I have an Ajax problem that I or anyone else can seem to solve.  It's similar to this post except that it's with PHP instead of ASP.  Do you mind taking a look at it?  It's located here:
http://www.experts-exchange.com/Programming/Languages/Scripting/AJAX/Q_23986253.html

You were the only one I could think of that could solve this problem.  Please help if you can.  Thanks.
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