Solved

AJAX Problem continuation

Posted on 2008-06-23
5
260 Views
Last Modified: 2010-04-21
Hello,


I used the exact same ajax code(http://www.experts-exchange.com/Programming/Languages/Scripting/AJAX/Q_23504279.html) at my job and it works fine except that after I enter in my comments and click "Update" the comment does not appear.  I have to hit refresh to see my changes.  I have been struggling with it all morning.
var xmlHttp=null; 

 

 function editComment(id) 

{ 

	xmlHttp=GetXmlHttpObject(); //See if it works with users browser. 

	if (xmlHttp==null) 

	{ 

		alert ("Browser does not support HTTP Request"); 

		return false; 

	} 

  xmlHttp.onreadystatechange=function(){stateChanged(id);}

	var url="schedAjax.asp"; 

	var data = "edtShed=Yes&cm_id="+id+"&cmt="+encodeURIComponent( document.getElementById("cmt"+id).value ); 

	xmlHttp.open("POST",url,true); 

	xmlHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 

	xmlHttp.setRequestHeader("Content-length", data.length); 

  xmlHttp.send( data ); 

}

 

 

function stateChanged(id) 

{ 

if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")

 { 

 document.getElementById("showCmt"+id).innerHTML=xmlHttp.responseText 

 hideEdit(id);

 } 

}

 

 

function GetXmlHttpObject()

{

var xmlHttp=null;

try

  {

  // Firefox, Opera 8.0+, Safari

  xmlHttp=new XMLHttpRequest();

  }

catch (e)

  {

  // Internet Explorer

  try

    {

    xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");

    }

  catch (e)

    {

    try

      {

      xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");

      }

    catch (e)

      {

      alert("Your browser does not support AJAX!");

      return false;

      }

    }

  }

 

  return xmlHttp;

}

 

 function show(id)

 {

 	document.getElementById(id).style.display="";

 }

 function hide(id)

 {

 	document.getElementById(id).style.display="none";

 }

 

 function showEdit(id)

 {

		show('cmt'+id);

    show('Update'+id);

    hide('Edit'+id);

    hide('showCmt'+id);

 }

 function hideEdit(id)

 {

		hide('cmt'+id);

    hide('Update'+id);

    show('Edit'+id);

    show('showCmt'+id);

 }

 

 

<!------------------------------------------------------------------------------------------------------------->            

<DIV>                     

<TABLE>

CODE.....

 

           <%

	           Set rs=Server.CreateObject("ADODB.Recordset") 

	           sSQL = "SELECT * FROM misComment WHERE ID = " & CLng(d) & " ORDER BY vDATE DESC"

	           rs.Open sSQL, objConn

	           do while not rs.EOF

           %>

             

             <form>

             <tr>

               <td width="10%"><%=rs("vdate")%></td>

               <td width="10%"><%=rs("usr")%></td>    

               <td>

               	<span id="showCmt<%=rs("id")%>">

               		<%=rs("comment")%>

               	</span>

               		<textarea style="display:none" id="cmt<%=rs("id")%>" cols="50" rows="5"><%=rs("comment")%></textarea>

               </td>

					     <td>

					     		<input type="button" id="Edit<%=rs("id")%>" value="Edit" onclick="showEdit('<%=rs("id")%>')"  name="edit" />

					     		<input type="button" value="Update" name="edit" id="Update<%=rs("id")%>" style="display:none;" onclick="editComment('<%=rs("id")%>')"  /></td>

             </tr>

             </form>

             

             <%

					    rs.MoveNext

			    		Loop

    				 %>

 

MORE CODE-----

</TABLE>

</DIV>

<!------------------------------------------------------------------------------------------------------------->

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0
Comment
Question by:Isaac
  • 3
  • 2
5 Comments
 
LVL 82

Accepted Solution

by:
hielo earned 500 total points
ID: 21847618
You are sending the edits to schedAjax.asp. schedAjax.asp MUST echo back the comment.  So, the last statement in schedAjax.asp
should be:
Response.Write( Request("cmt") )
0
 
LVL 5

Author Comment

by:Isaac
ID: 21848369
Hielo,

You are a life saver.  Thanks!!!
0
 
LVL 5

Author Closing Comment

by:Isaac
ID: 31469802
Hielo is excellent at AJAX.
Your code and explanations make sense.
Thanks.
0
 
LVL 82

Expert Comment

by:hielo
ID: 21848423
You are welcome!
0
 
LVL 5

Author Comment

by:Isaac
ID: 23185233
Hello Hielo,

I hope all is well.  I have an Ajax problem that I or anyone else can seem to solve.  It's similar to this post except that it's with PHP instead of ASP.  Do you mind taking a look at it?  It's located here:
http://www.experts-exchange.com/Programming/Languages/Scripting/AJAX/Q_23986253.html

You were the only one I could think of that could solve this problem.  Please help if you can.  Thanks.
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