Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
?
Solved

Unable to Transform XML to desire output

Posted on 2008-06-23
3
Medium Priority
?
553 Views
Last Modified: 2013-11-18
Hi,

I'm using an XSL to Transform an XML file to desire output. Everything working fine expect one thing!

Sample XML and XSL attached in code Snippet.

My Problem:
I unable to add a message which i would like to see at the last line in output file

Currently generating output file
-------------------------------------
ID=1
Name="Test"
Address="My Address"

ID=2
Name="Test1"
Address="My Address2"

My Desired output file.....
-------------------------------
ID=1
Name="Test"
Address="My Address"

ID=2
Name="Test1"
Address="My Address2"

Message: "Welcome come you all!"

==================
if you look at the above desired output file - I would like to see the "Message ......." tobe print at the last line of output file!

Here Sample XML File
 
<?xml version="1.0" encoding="UTF-8"?>
<Msg>
    <Data>
        <DataSet>
            <DataTable>
                <DataRow>
                    <ID>1</ID>
                    <Name>Test</Name>
                    <Address>My Address</Address>
                </DataRow>
                <DataRow>
                    <ID>2</ID>
                    <Name>Test1</Name>
                    <Address>My Address2</Address>
                </DataRow>
            </DataTable>
        </DataSet>
    </Data>
</Msg>
 
XSL file which i'm using to transfter above xml file to desire format
 
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:output method="text" />
    <xsl:template match="DataRow">
  	ID='<xsl:value-of select="ID" />',
  	Name='<xsl:value-of select="Name" />',
  	Address='<xsl:value-of select="Address" />'
 
    <xsl:text></xsl:text></xsl:template>
</xsl:stylesheet>

Open in new window

0
Comment
Question by:Yogeshup
  • 2
3 Comments
 
LVL 82

Accepted Solution

by:
hielo earned 500 total points
ID: 21848024
try:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:output method="text" />
    <xsl:template match="//Msg/Date/DataSet/DataTable">
    	<xsl:apply-templates select="DataRow"/>
	<xsl:text>Welcome You all</xsl:text>
    </xsl:template>
    <xsl:template match="DataRow">
        ID='<xsl:value-of select="ID" />',
        Name='<xsl:value-of select="Name" />',
        Address='<xsl:value-of select="Address" />'
 
    <xsl:text></xsl:text></xsl:template>
</xsl:stylesheet>

Open in new window

0
 
LVL 1

Author Comment

by:Yogeshup
ID: 21848633
Hi,

When I apply the above xsl it generate output file somthing like below....

ID='1', Name='Test', Address='My Address' ID='2', Name='Test1', Address='My Address2'

No message in output file
0
 
LVL 82

Expert Comment

by:hielo
ID: 21849792
I misspelled Data. I incorrrectly typed Date instead. Update your code with this:
<xsl:template match="//Msg/Data/DataSet/DataTable">
0

Featured Post

Free Tool: Subnet Calculator

The subnet calculator helps you design networks by taking an IP address and network mask and returning information such as network, broadcast address, and host range.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I found this questions asking how to do this in many different forums, so I will describe here how to implement a solution using PHP and AJAX. The logical flow for the problem should be: Write an event handler for the first drop down box to get …
JavaScript has plenty of pieces of code people often just copy/paste from somewhere but never quite fully understand. Self-Executing functions are just one good example that I'll try to demystify here.
Viewers will learn about if statements in Java and their use The if statement: The condition required to create an if statement: Variations of if statements: An example using if statements:
Viewers will learn about the regular for loop in Java and how to use it. Definition: Break the for loop down into 3 parts: Syntax when using for loops: Example using a for loop:
Suggested Courses

564 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question