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Soap request from Java from asp web service

Posted on 2008-06-24
6
1,269 Views
Last Modified: 2013-12-22
Hi expert, J have a problem with java & asp :
I want to call an as webservice from java app

but when j try i cath error,
Server returned HTTP response code: 405 for URL:.....
my web service is on
http://www.cma.hmade.biz/SyncWebService/HMSyncWebService.asmx
and the method that i want to call is dosyncfromzipfile

J think that the problem shoud be URL address or SoapAction
try
		{
			URL u = new URL("http://www.cma.hmade.biz/SyncWebService/");
			URLConnection uc = u.openConnection();
			HttpURLConnection httpCon = (HttpURLConnection)uc;
			httpCon.setDoOutput(true);
			httpCon.setDoInput(true);
			httpCon.setRequestMethod("POST");
			
			httpCon.setRequestProperty("Content-Type", "text/hml; charset=utf-8");
			httpCon.setRequestProperty("Content-Length", String.valueOf(382));
			httpCon.setRequestProperty("SOAPAction", "http://www.hmade.biz/doSyncFromZipFile");
			
			OutputStream out = httpCon.getOutputStream();
			Writer wout = new OutputStreamWriter(out);
			
		    wout.write("<?xml version=\"1.0\" encoding=\"utf-8\"?>");
		    wout.write("<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">");
		    wout.write("<soap:Body>");
		    wout.write("<doSyncFromZipFile xmlns=\"http://www.hmade.biz/\">");
		    wout.write("<updateXmlCmd>string</updateXmlCmd>");
		    wout.write("</doSyncFromZipFile>");
		    wout.write("</soap:Body>");
		    wout.write("</soap:Envelope>");
		    
			wout.flush();
			wout.close();
			
			InputStream in = httpCon.getInputStream();
			int c;
			while ((c=in.read())!=-1) System.out.write(c);
			in.close();
			
		}
		catch(Exception e)
		{
			System.err.println(e);
		}

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Question by:hmade
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6 Comments
 
LVL 23

Expert Comment

by:Siva Prasanna Kumar
ID: 21855216
may i know why you are using this approach of posting a XML directly to the Web service ? instead  you might have used the HTTP POST style mentioned at

http://www.cma.hmade.biz/SyncWebService/HMSyncWebService.asmx?op=doSyncFromZipFile

your SOAP msg looks appropriate but b7y http 405 what we can under stand is that your web server is not accepting your POST request. I feel this is wrong

  URL u = new URL("http://www.cma.hmade.biz/SyncWebService/");

in the sense the above URL doesn't accept a post url,  infact if you are posting via direct HTTP request I suggest to go with the HTTP POST approach mentioned in the first link .
POST /SyncWebService/HMSyncWebService.asmx/doSyncFromZipFile HTTP/1.1
Host: www.cma.hmade.biz
Content-Type: application/x-www-form-urlencoded
Content-Length: length
 
updateXmlCmd=string

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Author Comment

by:hmade
ID: 21855722
Thank's guru, the problemi is that my string param is a xml string and so i don't know if HTTP POST approach is the right way
0
 
LVL 23

Expert Comment

by:Siva Prasanna Kumar
ID: 21855898
it will not matter if its a XML or a normal string it will be considered as a plain text only, better try with HTTP POST approach.
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Author Comment

by:hmade
ID: 21856098
can you send me a sample for this solution?
0
 
LVL 23

Accepted Solution

by:
Siva Prasanna Kumar earned 300 total points
ID: 21861677
I think this question should have been 500 points ;) Just kidding here is your solution
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.Writer;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
 
 
public class TestHttpClient {
public static void main(String[] args) throws IOException {
	  URL u = new URL("http://www.cma.hmade.biz/SyncWebService/HMSyncWebService.asmx/doSyncFromZipFile");
      URLConnection uc = u.openConnection();
      HttpURLConnection httpCon = (HttpURLConnection)uc;
      httpCon.setDoOutput(true);
      httpCon.setDoInput(true);
      httpCon.setRequestMethod("POST");
      String data="<abc>aaaa</abc>";
      httpCon.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
      httpCon.setRequestProperty("Content-Length", String.valueOf(data.length()));
      httpCon.setRequestProperty("Host", "www.cma.hmade.biz");
      OutputStream out = httpCon.getOutputStream();
      Writer wout = new OutputStreamWriter(out);
      wout.write("updateXmlCmd="+data);
      wout.flush();
      wout.close();
      
      InputStream in = httpCon.getInputStream();
      byte[] response = new byte[httpCon.getContentLength()];
      
      in.read(response);
      
      System.out.println(new String(response));
      
}
}

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Author Comment

by:hmade
ID: 21863089
Excellent!!!
That is exactly what i'm looking for...
thanks a lot
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