Solved

SQL to multiply values on each row and then find the average

Posted on 2008-06-26
4
1,341 Views
Last Modified: 2010-04-21
Hi there,

I have a table Customer with the following details

AcctID,  Name, Ticket, Values

1            Bob       3           20
2            Bob       3           10
3           Bob        4            5
4           Bob        5          10
5           Bob        5          10
6           Karen     6           2

What I need to do is write a SQL query to multiply the values together for each ticket and then return the Average Value per user(Name). - The Average Value is the multiplied values for each ticket divided by the number of tickets.

Please can you help me write the SQL query to return the average values per user.

Many thanks.
0
Comment
Question by:ihatelag
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
4 Comments
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 21873274
you mean:
select name, avg(Ticket * Values)
 from customer
group by name

Open in new window

0
 

Author Comment

by:ihatelag
ID: 21874960
I need to multiply the figures in the Value column not Column Ticket and Column Values,

For example  for ticket 3 - bob has 10 * 20 in the 'Values' column  so ticket 3 = 200 from 1 ticket
then we take each ticket he has run the above formulae and then get the avarage value after multiplying the values.

Only if the query was just as simple as you wrote it ;)
0
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 21875090
it's as simple as that, with a "small" math trick:
set nocount on
declare @t table (acctID int ,  Name varchar(30), Ticket int, [Values] int)
insert into @t values(1            ,'Bob',       3         ,  20 )
insert into @t values(2            ,'Bob',       3         ,  10)
insert into @t values(3           ,'Bob',        4         ,   5)
insert into @t values(4           ,'Bob',        5         , 10)
insert into @t values(5           ,'Bob',        5         , 10)
insert into @t values(6           ,'Karen',     6          , 2)
 
-- step 1 to show the products:
select name, ticket, cast( exp(sum(log([values]))) as int) p
from @t
group by name, ticket
 
 
-- step 2 to average by user
select name, avg(p) average_value, count(*) count_tickets, sum(p) sum_product
from (
select name, ticket, cast( exp(sum(log([values]))) as int) p
from @t
group by name, ticket
) l
group by name

Open in new window

0
 

Author Closing Comment

by:ihatelag
ID: 31470912
I wasn't able to apply all of the query as the table didn't just contain the lines of the example, but I used a neat the step 1 and step 2 to good use. Many thanks for your help.
0

Featured Post

Best Practices: Disaster Recovery Testing

Besides backup, any IT division should have a disaster recovery plan. You will find a few tips below relating to the development of such a plan and to what issues one should pay special attention in the course of backup planning.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In this article I will describe the Copy Database Wizard method as one possible migration process and I will add the extra tasks needed for an upgrade when and where is applied so it will cover all.
In this article we will get to know that how can we recover deleted data if it happens accidently. We really can recover deleted rows if we know the time when data is deleted by using the transaction log.
Using examples as well as descriptions, and references to Books Online, show the documentation available for date manipulation functions and by using a select few of these functions, show how date based data can be manipulated with these functions.
Viewers will learn how to use the INSERT statement to insert data into their tables. It will also introduce the NULL statement, to show them what happens when no value is giving for any given column.

740 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question