Hide some output in batch file

This question is in relation to https://www.experts-exchange.com/questions/23566786/modify-output-of-del-command.html
I now have the correct output of my script and it does exactly what i want, but i have to much output.
I'm getting this as output if there was nothing to delete:
--
[Cleanup] Cleaning up download directory: Y:\Newsleecher\downloads\complete\Games\SafeCracker
[Cleanup] Deleteing .nzb files
Bestand niet gevonden (File not found)
[Cleanup] Deleteing .sfv files
Bestand niet gevonden (File not found)
[Cleanup] Deleteing .url files
Bestand niet gevonden (File not found)
[Cleanup] Deleteing .db files
Bestand niet gevonden (File not found)
[Cleanup] Deleted 0 files (0 nzb, 0 sfv, 0 url, 0 db)
--
but i'm expecting this as output:
--
[Cleanup] Cleaning up download directory: Y:\Newsleecher\downloads\complete\Games\SafeCracker
[Cleanup] Deleteing .nzb files
[Cleanup] Deleteing .sfv files
[Cleanup] Deleteing .url files
[Cleanup] Deleteing .db files
[Cleanup] Deleted 0 files (0 nzb, 0 sfv, 0 url, 0 db)
--

@echo off
setlocal
set fcount=0
set nzbcount=0
set sfvcount=0
set urlcount=0
set dbcount=0
 
echo.
echo [Cleanup] Cleaning up download directory: %1
 
echo [Cleanup] Deleteing .nzb files
for /f %%V in ('dir %1*.nzb /b /s ^| find /v /c ""') do set/a nzbcount = %%V
del /s /q "%1"*.nzb > NUL 2>NUL
 
echo [Cleanup] Deleteing .sfv files
for /f %%V in ('dir %1*.sfv /b /s ^| find /v /c ""') do set/a sfvcount = %%V
del /s /q "%1"*.sfv > NUL 2>NUL
 
echo [Cleanup] Deleteing .url files
for /f %%V in ('dir %1*.url /b /s ^| find /v /c ""') do set/a urlcount = %%V
del /s /q "%1"*.url > NUL 2>NUL
 
echo [Cleanup] Deleteing .db files
for /f %%V in ('dir %1*.db /b /s ^| find /v /c ""')  do set/a dbcount  = %%V
del /s /q "%1"*.db > NUL 2>NUL
 
set/a fcount = %nzbcount% + %sfvcount% + %urlcount% + %dbcount%
 
echo [Cleanup] Deleted %fcount% files (%nzbcount% nzb, %sfvcount% sfv, %urlcount% url, %dbcount% db)
echo.

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