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Access 2007 VBA XIRR Function Error

I found the code below on an old post from the year 2000.  I'm an trying to input into my database but I receive a Run Time Error '13': Type Mismatch.  My thought is the syntax may be different in the different versions of Access, but I'm a newbie, so don't know...
On the debug it points to the line:  Set rstXIRR = dbs.openrecordset("TableXIRR", dbOpenDynaset).
Does anyone have any thoughts of what could generate the type mismatch error?
Thank you.
Option Compare Database
Function XIRR(aXIRR As Variant, nRate As Double, nPayments As Integer) As Double
Dim i As Integer
XIRR = 0                                        ' residual of function
For i = 1 To nPayments
  XIRR = XIRR + aXIRR(i, 2) / (1 + nRate) ^ (aXIRR(i, 1) / 365)
Next i
End Function
Private Sub CommandRunXIRR_Click()
Dim dbs As Database
Dim rstXIRR As Recordset
Dim aXIRR() As Double
Dim nPayments As Integer
Dim dFirstPayDate As Date
Dim i As Integer, j As Integer
Dim nRate As Double, nLastRate As Double, nRateStep As Double
Dim nXIRR As Double
Dim nResidual As Double, nLastResidual As Double
Set dbs = CurrentDb
Set rstXIRR = dbs.OpenRecordset("TableXIRR", dbOpenDynaset)
nPayments = DCount("PayDate", "TableXIRR")
ReDim aXIRR(nPayments, 3)
dFirstPayDate = DMin("PayDate", "TableXIRR")
nRate = 0.1                                                                     ' initial guess
nRateStep = 0.1                                                              ' arbitrary guess
i = 1
With rstXIRR
While Not .EOF
  aXIRR(i, 1) = DateDiff("d", dFirstPayDate, !PayDate)
  aXIRR(i, 2) = !Payment
  i = i + 1
End With
nResidual = 10
nLastResidual = 1
nLastRate = nRate
i = 0
While i < 100 And Abs((nLastResidual - nResidual) / nLastResidual) > 10 ^ -8
nLastResidual = nResidual
nResidual = XIRR(aXIRR, nRate, nPayments)
nLastRate = nRate
If nResidual >= 0 Then
  nRate = nRate + nRateStep
  nRateStep = nRateStep / 2
  nRate = nRate - nRateStep
End If
i = i + 1
nXIRR = nLastRate
Debug.Print "The internal rate of return is "; Format(nXIRR, "#.##%")
End Sub

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Thank you so's great!