Receive xml which is sent using HTTP Post (from one of our vendor) in a JSP /JAVA Servlet and Send respond back an XML Back using http post

IF the xml is coming over a post. you can recieve it in your servlet by using request.getParameter("XML"); where XML is the variable name that has been used to send the xml.
this variable can be recieved in a string and then you can manupulate it to do what ever you want.

No its not sent using request parameter .its the xml file which is sent accross

thanks for your reply Kuldeepchaturvedi

okay then you can just do a request.getinputStream();
and then read the XML off this stream...
once you are done processing it, you can write it back to response.getOutputStream();

Thanks Kuldeepchaturvedi,

 thanks for your quick responce...can you provide me a sample code for  request.getinputStream();
and response.getOutputStream();...thanks in advance

int contentLength = request.getContentLength();
byte[] buffer = new byte[contentLength];
            java.io.InputStream inputStream = request.getInputStream();
            inputStream.read(buffer);
            String content = new String(buffer);

Now this string content should have the XML that was sent in...

after processing it you can do
OutputStream os = response.getOutputStream();
and then write your response using.
os.write()

thank you

1) request.getInputStream(); worked fine
2)where as response.getOutputStream(); didnt work

this is wat i have done please go through the code for server sided and client sided


This is what i am getting for my below :
java.io.IOException: Server returned HTTP response code: 500 for URL:XXXXXXXXXXXXXXXXXXXX

 

-------------Server side(servlet)-----------
response.setContentType("text/xml");
 
OutputStream os = response.getOutputStream();
 
OutputStreamWriter wout = new OutputStreamWriter(os, "UTF-8");
 
String xml_string    = <?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\" ?> <Request> <Envelope> <EnvelopeID>_1</EnvelopeID> <NAME>VICTOR</NAME> </Envelope> </Request>"; 
 
 wout.write(xml_string);
--------------------------
 
----------------Client Side--------------
Result_From_Server = new BufferedReader(new InputStreamReader(UrlConnection.getInputStream()));
 
StringBuffer Result_String_Buffer   = new StringBuffer();
String inputLine  = null;
while ((inputLine = Result_From_Server.readLine()) != null)
Result_String_Buffer.append(inputLine);
 
Result_From_Server.close();
 
String result_string = new String(Result_String_Buffer);
 
out.println(result_string);
-----------------------

Select allOpen in new window

do a wout.close() after writing.
also that xml string does not look correct, ( the opening " is missing I guess);

That should fix it.

Thanks It works fine ...thanks you very much bro