Solved

Java Swing JTextArea didn't show up???

Posted on 2008-09-29
8
324 Views
Last Modified: 2013-11-23
Can you help me to debug my simple code please? The JTextArea displayArea didn't show up :(

import javax.swing.*;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;

public class Display implements  ActionListener{

      JPanel GUI;
      JTextArea displayArea;
      JLabel separatorLabel;
      JTextField separatorField;
      JButton enterButton;
      String content = "Hello";

      public JPanel createContentPane (){

            GUI = new JPanel();
            GUI.setLayout(null);

            displayArea = new JTextArea(content);
            displayArea.setEditable(false);
            displayArea.setLineWrap(false);
            displayArea.setWrapStyleWord(true);

            JScrollPane scrollBar = new JScrollPane(displayArea, JScrollPane.VERTICAL_SCROLLBAR_AS_NEEDED,
                        JScrollPane.HORIZONTAL_SCROLLBAR_AS_NEEDED);

            scrollBar.setPreferredSize(new Dimension(0, 300));
            GUI.add(scrollBar);

            separatorLabel = new JLabel("Please enter a character ");
            separatorLabel.setForeground(Color.red);
            separatorLabel.setLocation(20, 525);
            separatorLabel.setSize(220, 40);
            GUI.add(separatorLabel);

            separatorField = new JTextField(8);
            separatorField.setLocation(250, 530);
            separatorField.setSize(50, 30);
            GUI.add(separatorField);

            enterButton = new JButton("Enter");
            enterButton.setLocation(310, 530);
            enterButton.setSize(80, 30);
            enterButton.addActionListener(this);
            GUI.add(enterButton);
            GUI.setOpaque(true);    
            return GUI;
      }
      public void actionPerformed(ActionEvent e) {
            if(e.getSource() == enterButton)
            {
                        System.out.println("ok");
                        System.exit(0);
            }
      }
      private static void createAndShowGUI() {
            JFrame.setDefaultLookAndFeelDecorated(true);
            JFrame frame = new JFrame("Request message cookies");
            Display display = new Display();
            frame.setContentPane(display.createContentPane());
            frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
            frame.setSize(800, 600);
            frame.setVisible(true);
      }
      public static void main(String[] args) {
            SwingUtilities.invokeLater(new Runnable() {
                  public void run() {
                        createAndShowGUI();
                  }
            });
      }
}
0
Comment
Question by:tdavidson_9
  • 4
  • 4
8 Comments
 
LVL 59

Accepted Solution

by:
Kevin Cross earned 250 total points
ID: 22601717
Think you have to set a layout manager:
GUI.setLayout(new FlowLayout()); // use something appropriate for your application

scrollBar.setPreferredSize(new Dimension(400, 300)); // add a width to your dimension

The two of these together and you will see JTextArea.
0
 

Author Comment

by:tdavidson_9
ID: 22601862
It works! But it screwed up the other objects location e.g. separatorField.setLocation(250, 530) no longer displayed at (250, 530) :(
0
 
LVL 59

Expert Comment

by:Kevin Cross
ID: 22601898
Here take a look at the other LayoutManager options:
http://java.sun.com/docs/books/tutorial/uiswing/layout/using.html
0
Free Tool: Postgres Monitoring System

A PHP and Perl based system to collect and display usage statistics from PostgreSQL databases.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

 

Author Comment

by:tdavidson_9
ID: 22601911
Thanks a lot!!!
0
 
LVL 59

Expert Comment

by:Kevin Cross
ID: 22601922
No problem.  You are welcome.
0
 

Author Comment

by:tdavidson_9
ID: 22602342
Hello mwvisa1,

I am so sorry that can I ask you just one more question? If I want to set the value of the variable content i.e.  String content = "Hello"; equal to the argument of args[0] instead of "hello", is it possible to do it? Thanks!
0
 
LVL 59

Expert Comment

by:Kevin Cross
ID: 22602420
Yes it is possible.

If you have difficulty implementing you can start a new Q.
0
 

Author Comment

by:tdavidson_9
ID: 22602521
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
hibernate insert example 13 34
Java Restore security prompts not working 10 56
Chrome and Firefox Java 5 50
Java class and jar 3 22
Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
In this post we will learn how to connect and configure Android Device (Smartphone etc.) with Android Studio. After that we will run a simple Hello World Program.
Viewers will learn about the regular for loop in Java and how to use it. Definition: Break the for loop down into 3 parts: Syntax when using for loops: Example using a for loop:
This tutorial will introduce the viewer to VisualVM for the Java platform application. This video explains an example program and covers the Overview, Monitor, and Heap Dump tabs.

856 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question