Solved

function in vb.net

Posted on 2008-09-29
2
193 Views
Last Modified: 2010-04-23
hello there,
Im trying to convert this little peace of code to vb.net can someone help me out please..
thanks
<?PHP

$checkthisnumber = 100;

$i=1;

while ($i < 151) 

{

        

 if ($i == $checkthisnumber) 

        {

                echo "number found,: ". $checkthisnumber;

		break;

        } else {

                echo $i." was not found";

        }

$i++;

}

 

?>

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Question by:XK8ER
2 Comments
 
LVL 59

Accepted Solution

by:
Kevin Cross earned 500 total points
ID: 22602550
You could do this in a VB.NET sub like this:
'CheckNumber(100) <--- $checkthisnumber = 100;

Sub CheckNumber(ByVal number As Integer)

     Dim i As Integer = 1 '$i=1;
 

     While i < 151 'while ($i < 151) 

         If i = number Then 'if ($i == $checkthisnumber) 

             'echo "number found,: ". $checkthisnumber;

             Response.Write("number found,: " & CStr(number))

         Else 

             'echo $i." was not found";

             Response.Write(CStr(number) & " was not found")

         End
 

         i = i + 1 '$i++;

     End While

End Sub

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LVL 62

Expert Comment

by:Fernando Soto
ID: 22602579
Hi XK8ER;

This snippet should do the same thing.

Fernando

Dim checkthisnumber As Integer = 100

Dim i As Integer = 1
 

While i < 151

    If i = checkthisnumber Then

        Console.WriteLine("number found,: " & checkthisnumber.ToString())

    Else

        Console.WriteLine(i.ToString() & " was not found")

    End If

    i += 1

End While

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