Solved

function in vb.net

Posted on 2008-09-29
2
195 Views
Last Modified: 2010-04-23
hello there,
Im trying to convert this little peace of code to vb.net can someone help me out please..
thanks
<?PHP
$checkthisnumber = 100;
$i=1;
while ($i < 151) 
{
        
 if ($i == $checkthisnumber) 
        {
                echo "number found,: ". $checkthisnumber;
		break;
        } else {
                echo $i." was not found";
        }
$i++;
}
 
?>

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Question by:XK8ER
2 Comments
 
LVL 59

Accepted Solution

by:
Kevin Cross earned 500 total points
ID: 22602550
You could do this in a VB.NET sub like this:
'CheckNumber(100) <--- $checkthisnumber = 100;
Sub CheckNumber(ByVal number As Integer)
     Dim i As Integer = 1 '$i=1;
 
     While i < 151 'while ($i < 151) 
         If i = number Then 'if ($i == $checkthisnumber) 
             'echo "number found,: ". $checkthisnumber;
             Response.Write("number found,: " & CStr(number))
         Else 
             'echo $i." was not found";
             Response.Write(CStr(number) & " was not found")
         End
 
         i = i + 1 '$i++;
     End While
End Sub

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LVL 63

Expert Comment

by:Fernando Soto
ID: 22602579
Hi XK8ER;

This snippet should do the same thing.

Fernando

Dim checkthisnumber As Integer = 100
Dim i As Integer = 1
 
While i < 151
    If i = checkthisnumber Then
        Console.WriteLine("number found,: " & checkthisnumber.ToString())
    Else
        Console.WriteLine(i.ToString() & " was not found")
    End If
    i += 1
End While

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