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How to count by outer group in Oracle?

Posted on 2008-09-29
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How to count by outer group? I mean
when I use count now, it count the number of records in the group po.po_nbr, pt.pt_part.

By I just want to count the group po.po_nbr and appear in the "Number of Record" column, how to do that?
SELECT po.po_nbr "PO Number", pt.pt_part "Part Number", COUNT(pt.pt_part) "Number of Record", CEIL(COUNT(pt.pt_part) / 9) "Total Page"

FROM {mfgotrng}.QAD.PO_MSTR po, {mfgotrng}.QAD.POD_DET pod, {mfgotrng}.QAD.PT_MSTR pt

WHERE po.po_domain = pod.pod_domain AND pod.pod_domain = pt.pt_domain AND po.po_nbr = pod.pod_nbr AND pod.pod_part = pt.pt_part

AND pod.pod_type <> 'm'

GROUP BY po.po_nbr, pt.pt_part

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Question by:mawingho
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sdstuber earned 500 total points
ID: 22608924
SELECT po.po_nbr "PO Number", pt.pt_part "Part Number", COUNT(*) over (partition by po.po_nbr) "Number of Record" , CEIL(COUNT(pt.pt_part) / 9) "Total Page"
FROM {mfgotrng}.QAD.PO_MSTR po, {mfgotrng}.QAD.POD_DET pod, {mfgotrng}.QAD.PT_MSTR pt
WHERE po.po_domain = pod.pod_domain AND pod.pod_domain = pt.pt_domain AND po.po_nbr = pod.pod_nbr AND pod.pod_part = pt.pt_part
AND pod.pod_type <> 'm'
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Expert Comment

by:sdstuber
ID: 22608945
or maybe this...

select  po_nbr "PO Number", pt_part "Part Number", cnt "Number of Record", CEIL(cnt / 9) "Total Page"
from
(
SELECT po.po_nbr , pt.pt_part , COUNT(*) over (partition by po.po_nbr) cnt
FROM {mfgotrng}.QAD.PO_MSTR po, {mfgotrng}.QAD.POD_DET pod, {mfgotrng}.QAD.PT_MSTR pt
WHERE po.po_domain = pod.pod_domain AND pod.pod_domain = pt.pt_domain AND po.po_nbr = pod.pod_nbr AND pod.pod_part = pt.pt_part
AND pod.pod_type <> 'm')
0

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