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SUM up DISTINCT GROUP BY results MySQL

Posted on 2008-10-01
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Last Modified: 2010-04-21
I'm using a query:

SELECT DISTINCT COUNT(o.organizationId) as rowcount
FROM CatalogListings cl, Organization o
WHERE cl.active = '1'
GROUP BY alphabetizeUnderLetter


This returns 2 results lets say, since its grouping by...

___Rowcount__
  3
  2

I want to get the numbers merged into "5" at the MySQL level through the query.
Thanks guys!
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Question by:MattKenefick
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8 Comments
 
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Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 22614482
this should do it:
SELECT SUM(rowcount)
FROM (
SELECT DISTINCT COUNT(o.organizationId) as rowcount 
FROM CatalogListings cl, Organization o 
WHERE cl.active = '1'
GROUP BY alphabetizeUnderLetter
)

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Expert Comment

by:RemcovC
ID: 22614495
I'd say remove the GROUP BY clause
0
 
LVL 4

Author Comment

by:MattKenefick
ID: 22614596
For that query above.. I get:

#1248 - Every derived table must have its own alias


Remcov : Can't remove the GROUP BY. There is more to the query (searching) that makes it necessary.
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Author Comment

by:MattKenefick
ID: 22614676
Nevermind.. if I use an "as X" identifier at the end, it works.

Thanks !
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Author Closing Comment

by:MattKenefick
ID: 31501977
make sure to add an "AS tablename" or you'll catch errors
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Expert Comment

by:RemcovC
ID: 22615235
MattKanefick

I thought so, but a coworker of mine was absolutely sure that it was the solution and persuaded me to post it.

Sorry for the inconvenience
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LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 22615308
>I thought so, but a coworker of mine was absolutely sure that it was the solution and persuaded me to post it.

the problem with just removing the GROUP BY is if 2 values of alphabetizeUnderLetter have the same value of organizationId, that suggested method will return 1, and it should return 2 (1 for each Letter value)...

which leads to a "simpler" version:
SELECT DISTINCT COUNT( CONCAT( o.organizationId,alphabetizeUnderLetter)  ) as rowcount 
FROM CatalogListings cl, Organization o 
WHERE cl.active = '1'

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Author Comment

by:MattKenefick
ID: 22615354
Remcov: No problem. All possibly solutions are welcome. Who knows, maybe a wrong answer today will be the right answer tomorrow.
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