Number format regional settings in VB6

Posted on 2008-10-01
Last Modified: 2010-05-18
I have an app that is developed in vb6. When I do calculations I format numbers based on a '.' for the decimals. I now have customers in the Netherlands who format using ',' and when I do any calculations or submit the data I get errors.

How can I change this code for example:

myTotal = format(mysubtotal + mytax,"0.00")

Another One

rs!total = format(myTotal, "0.00')
I don't want to use the comma but would rather like code to do the math using the local regional settings.
Not all values are currency other some are qty's .

Please can anyone help


Question by:cwaldick
  • 2
LVL 13

Expert Comment

ID: 22615463
If you want to use format function is to change Regional Settings of the. You might want to save current settings before calling the format function and restore them back afterward

you can find a code for changing  reg.settings here:

Another solution (better) would be to create your own function that format the numbers the way you need.
LVL 22

Accepted Solution

danaseaman earned 500 total points
ID: 22617145
It is not recommended changing Regional Settings on another users machine.
You can format a number using U.S. English - LCID-1033, or any other supported LCID regardless of the users configurations using the following code:

Option Explicit

Private Declare Function GetLocaleInfoA Lib "kernel32" (ByVal Locale As Long, ByVal LCType As Long, ByVal lpData As Any, ByVal cchData As Long) As Long

Private Declare Function GetNumberFormatA Lib "kernel32" (ByVal Locale As Long, ByVal dwFlags As Long, ByVal lpValue As String, ByRef lpFormat As NUMBERFMT, ByVal lpNumberStr As String, ByVal cchNumber As Long) As Long

Private Type NUMBERFMT

        NumDigits       As Long     ' number of decimal digits

        LeadingZero     As Long     ' if leading zero in decimal fields

        Grouping        As Long     ' group size left of decimal

        lpDecimalSep    As String   ' ptr to decimal separator string

        lpThousandSep   As String   ' ptr to thousand separator string

        NegativeOrder   As Long     ' negative number ordering

End Type

Private Sub Form_Load()

   Debug.Print FormatNumberByLCID("123456789", 1033) 'U.S. English

   Debug.Print FormatNumberByLCID("123456789", 1043) 'Dutch

End Sub

Public Function FormatNumberByLCID(ByVal sNumber As String, _

   Optional ByVal LCID As Long) As String

   Const LOCALE_SDECIMAL As Long = &HE

   Const LOCALE_STHOUSAND As Long = &HF&

   Const LOCALE_SGROUPING As Long = &H10

   Const LOCALE_IDIGITS As Long = &H11

   Const LOCALE_ILZERO As Long = &H12

   Const LOCALE_INEGNUMBER As Long = &H1010


   Dim Buffer          As String * 255




   With NF

      .NumDigits = Val(pfGLI(LCID, LOCALE_IDIGITS))

      .Grouping = Val(pfGLI(LCID, LOCALE_SGROUPING))

      .lpDecimalSep = Left$(pfGLI(LCID, LOCALE_SDECIMAL), 1)

      .lpThousandSep = Left$(pfGLI(LCID, LOCALE_STHOUSAND), 1)

      .NegativeOrder = Val(pfGLI(LCID, LOCALE_INEGNUMBER))

      .LeadingZero = Val(pfGLI(LCID, LOCALE_ILZERO))

   End With


   GetNumberFormatA LCID, 0, sNumber, NF, Buffer, 255

   FormatNumberByLCID = StripNull(Buffer)


End Function

Public Function pfGLI(ByVal LCID As Long, ByVal reqInfo As Long) As String

   Dim nRet             As Long

   Dim Buffer           As String


   nRet = GetLocaleInfoA(LCID, reqInfo, Buffer, 0&)

   If nRet Then

      Buffer = Space$(nRet)

      nRet = GetLocaleInfoA(LCID, reqInfo, Buffer, Len(Buffer))

      pfGLI = Left$(Buffer, nRet - 1)

   End If

End Function

Public Function StripNull(ByVal StrIn As String) As String

   Dim nul              As Long

   nul = InStr(StrIn, vbNullChar)

   Select Case nul

      Case Is > 1

         StripNull = Left$(StrIn, nul - 1)

      Case 1

         StripNull = ""

      Case 0

         StripNull = Trim$(StrIn)

   End Select

End Function

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LVL 17

Expert Comment

ID: 22620049
first check that is there comma ,
InStr(1, IP, ",", vbTextCompare)

and then replace , with .
using replace function
LVL 13

Expert Comment

ID: 22620083
>>first check that is there comma ,
>>InStr(1, IP, ",", vbTextCompare)

>>and then replace , with .
>>using replace function

What if regional setting are using comma as thousand separator? Then 1000 will be represented as 1,000.00
After applying your formula you will get 1.000.00 which is not legal decimal number at all.

danaseaman's solution is the way to do it right

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