Java - find item in array

I need to search an array of strings for a specific item (ID) and return an array of just the items found.  Can someone help me?  I'm very new to Java and am struggling with this.

Thank you,
Twitz76
Twitz76Asked:
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javaexpertoConnect With a Mentor Commented:
You must loop your array and then extract the id of the objects and compare with your id. If the id match then you add the object to the new array that you'll return if all this is inside a method.
//here you create the list that will contains the match objects
ArrayList<MyObject> myList = new ArrayList<MyObject>();
for (int i = 0; i < myArray.length; i++) { //iterate
     //here you extract the objects in the 0, 1, 2.... position
     MyObject mo = myArray[i]; 
     //here you compare the id in the objects with 3
     //remember you should have the method getId in you MyObject class
     if(mo.getId() == 3) {
           //here you add the objects to a list, I chose list because
           //it hasn't a fixed size remember you dont know how many
           //objects you'll add.
           myList.add(mo);
     }
}

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Kevin CrossChief Technology OfficerCommented:
Well you can use the Arrays/Collections API to 1) sort the array - Arrays.sort(strArray) and then 2) search for your item - Arrays.binarySearch(strArray, itemID).

If what you are saying is you want to match all items in array to an ItemID or range of ItemIDs, this may help: http://crossedlogic.blogspot.com/2008/09/range-searching-using-java.html.  There is an example of simple looping and then using binary search.  This was meant for more a range, but can give you helpful tidbits none the less.


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Ajay-SinghCommented:
You can use something like this,

List r = new ArrayList();
List l = ... // input;
for(Object o: l) {
  if(id.equals(o)) {
     r.add(o);
  }
}
// Now r contains all the elements you need
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Kevin CrossChief Technology OfficerCommented:
Twitz76, any of this helping?

Ajay's example is like simple loop example in my link above.  It works well, as you can strongly type the List using List<String> and then eliminate case sensitivity by using id.equalsIgnoreCase(o).  Once you have filled the List object r, you can get an array by using r.toArray().

Let us know if you need anything else clarified.

Regards,
Kevin
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Twitz76Author Commented:
Experts,
I'm trying to wrap myself around the concept before I try to write the code.  This is new to me so I'm trying to understand each piece and what it does.  I want to "know" what I am doing before I do it.
Thanks!
Twitz76
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Kevin CrossChief Technology OfficerCommented:
That is always best.  Just ask questions if something is not clear.
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