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Nawk - SED problems

Posted on 2008-10-01
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Last Modified: 2013-11-05
Hi all,

Could anyone tell me what's wrong with script below?

echo "Please enter username"
read name
echo "please enter new gid"
read id

sed 's/$name:.*:.*:$id:.*:.*:.*' /etc/passwd > logfile

or

nawk -F: -v user=$"name" '$1 == user{print $1 $4 == "$id}' /etc/passwd

i think i have a syntax error

please help
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Question by:c00kie88
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Expert Comment

by:Tintin
ID: 22621173
When you use single quotes, the variables $name and $id are treated literally.

Are you actually trying to modify the contents of /etc/passwd?  If so, then I would strongly suggest you don't use this approach and use the usermod command.
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Author Comment

by:c00kie88
ID: 22621865
i can;t use usemod as you need root permission..

I have to make a script for non-root user to be able to change all those fields..

I'm having a problem with sed syntax. Anyone can help me?
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LVL 48

Expert Comment

by:Tintin
ID: 22622023
You would be much better off using sudo and usermod.  How is a non-root user going to make the changes anyway?

I have given you an answer to the problem with your use of sed.  Use double quotes instead of single quotes.
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Author Comment

by:c00kie88
ID: 22622055
yeah.. but it does not fix the overall problem..

Does not matter..
Thanks anyway..

I will figure it out myself

Thanks for trying
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Tintin earned 125 total points
ID: 22622159
Here's the fix for your sed statement (I've tested it)


sed "s/\($user:.:[0-9]*:\)[0-9]*:\(.*\)/\1$id\2/" /etc/passwd

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by:Mysidia
ID: 22656333
awk -F: '/^'${name}':/ {OFS=":";  $4='${id}';  print $0   }'  /etc/passwd


Regarding earlier scripts,  the reason you're having problems:

sed 's/$name:.*:.*:$id:.*:.*:.*' /etc/passwd > logfile
^^^^^^^^^^^^^^^^^^^
this is not a well-formed substitution.
$ variables are interpreted by your shell, not sed.
you'd need to use double quotes,  single-quotes mean $name and
$id won't be expanded.. instead you're looking for a user named "$name"

Second, when performing a substitution with sed, you need two clauses,
you only have one

a sed substitution looks like this:

sed 's/XAX/XBX/'

which means "Replace the match XAX with XBX"

syntactically what your script uses is
sed 's/XAX'

So you need to terminate the first part of the s// command, then
enter the target substitution, and terminate that with a / also.





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