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Counting Days So Far This Year..

Posted on 2008-10-01
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6,834 Views
Last Modified: 2008-10-24
I want to count how many days have passed this year so far.

I've attached how I'm doing right now.. it seems a bit.. robust.

Is there a better way to do this?  Is there a way to calculate business days.
<?php

if( function_exists( 'date_default_timezone_set' ) )

{

	// Set the default timezone to US/Eastern

	date_default_timezone_set( 'US/Eastern' );

}

 

// Will return the number of days between the two dates passed in

function count_days( $a, $b )

{

    // First we need to break these dates into their constituent parts:

    $gd_a = getdate( $a );

    $gd_b = getdate( $b );

 

    // Now recreate these timestamps, based upon noon on each day

    // The specific time doesn't matter but it must be the same each day

    $a_new = mktime( 12, 0, 0, $gd_a['mon'], $gd_a['mday'], $gd_a['year'] );

    $b_new = mktime( 12, 0, 0, $gd_b['mon'], $gd_b['mday'], $gd_b['year'] );

 

    // Subtract these two numbers and divide by the number of seconds in a

    //  day. Round the result since crossing over a daylight savings time

    //  barrier will cause this time to be off by an hour or two.

    return round( abs( $a_new - $b_new ) / 86400 );

}

 

// Prepare a few dates

$date1 = strtotime( '1/01/2008 12:01am' );

$date2 = strtotime( '10/01/2008 8:36pm' );

$dayspassed = count_days($date1, $date2); 

echo $dayspassed;

?>

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Comment
Question by:cstormer
  • 2
3 Comments
 

Author Comment

by:cstormer
ID: 22621241
With the above solution I also ahve issues with it not automatically knowing today's date...

$date1 = strtotime( '1/01/2008 12:01am' );
$date2 = strtotime( '10/01/2008 8:36pm' );

Any help here would be great... (and if there is a way for it to always know what the 1st of the year is)...
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LVL 3

Accepted Solution

by:
sistemu earned 500 total points
ID: 22622043
Hi,
Here is a much shorter version.
<?php

$var1 = strtotime(date ("Y-m-d H:i:s"));

$var2 = strtotime("01/01/".date('Y') );

$rez = round(($var1 - $var2) / (60*60*24)); //seconds in a day
 

echo 'Today: '.$var1.'<br>';

echo 'Rez: '.$rez;

?>

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LVL 3

Assisted Solution

by:sistemu
sistemu earned 500 total points
ID: 22622121
I'm sorry... that wasn't a final version, I skipped a few things.
Hope you like it.
<?php

function return_days_passed($new_date = 0){

    if($new_date != 0)

        $new_date = strtotime($new_date);

    else

        $new_date = strtotime(date ("Y-m-d H:i:s"));

    $first_day = strtotime("01/01/".date('Y H:i:s',$new_date) );

    return round(($new_date - $first_day) / (60*60*24)); //seconds in a day

}

echo return_days_passed().'<br>';

echo return_days_passed('05/01/2005 8:36pm');

?>

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