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How to get OpenXML to process all nodes within parent node

Posted on 2008-10-02
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Last Modified: 2013-11-05
Hi there
I pass an XML string to my stored procedure with the following format:
<Root>
<Scheme ref='someref''>
<Payment>
<FundName>Fund1</FundName>
<Amount>0</Amount>
</Payment>
<Payment>
<FundName>Fund2</FundName>
<Amount>0</Amount>
</Payment>
.....
</Scheme>
<Scheme ref='anotherref'>
.....
</Scheme>
</Root>

In my stpred procedure I need to load this XML into a table with the following format:

CREATE TABLE #TempSchemes([Scheme] varchar(100) ,
                      [FundName] varchar(30) ,
                      [Amount] varchar(18))

My OpenXML statement look slike this:

EXEC sp_xml_preparedocument @nXmlHandle output, @SchemeData

INSERT INTO #TempSchemeData([Scheme], [FundName], [Amount])
SELECT xScheme, xFundName, xAmount
FROM OPENXML (@nXmlHandle, '/Root/Scheme',1)  
WITH (xScheme varchar(20) './@ref',
xFundName varchar(30) './Payment/FundName',
xAmount varchar(18) './Payment/Amount')

SELECT @nErr = @@Error, @nRowCnt = @@Rowcount
 IF(@nErr <> 0)
 BEGIN
         SELECT @nRetVal = 1  
         EXEC sp_xml_removedocument @nXmlHandle
         GOTO ERR_HANDLER
END              

THis works without error but all I am getting in my table is the FundName and Amount from my very first
<Payment> tag for each scheme when what I want is for it to load every <payment> item and give it the scheme ref of the enclosing <Scheme> tag.

Any ideas much appreciated.

Cheers
Sam
EXEC sp_xml_removedocument @nXmlHandle
        
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Question by:Samm1502
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2 Comments
 
LVL 23

Accepted Solution

by:
Snarf0001 earned 2000 total points
ID: 22624086
Try this one:

select xScheme, xFundName, xAmount
from openxml(@idoc, 'Root/Scheme/Payment', 1)
with (
      xScheme varchar(20) '../@ref',
      xFundName varchar(30) 'FundName',
      xAmount varchar(18) 'Amount'
)
0
 

Author Closing Comment

by:Samm1502
ID: 31502330
Thanks!
0

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