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Invalid argument error with creatingdatabase in vb6

Posted on 2008-10-04
2
219 Views
Last Modified: 2012-05-05
Hello,

For some reason I get an invalid argument error with attached code or attached pic.
Error line is marked with : ERROR LINE

Could someone help me out?
Regards,
Dennis
Function Create_Database()
 
Dim dbnewDB As Database
Dim tdnewtable As tabledef
Dim fld As field
Dim idx As Index
 
 
Set dbnewDB = createdatabase("c:\structure\Dennis.mdb", dblanggeneral)
Set tdnewtable = New tabledef
Set fld = tdnewtable.createfield("Title", dbtext, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("Open", dbMemo, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("High", dbMemo, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("Low", dbMemo, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("Close", dbMemo, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("Signal_1", dbMemo, 20)
tdnewtable.fields.append fld
Set fld = tdnewtable.createfield("Equity_1", dbMemo, 20)
tdnewtable.fields.append fld
Set idx = tdnewtable.createindex
With idx
.Name = "idxTitle"
.fields.append.createfield ("Title") 'ERROR LINE
 
End With
tdnewtable.indexes.append idx
tdnewtable.Name = "tblcollection"
dbnewDB.tabledefs.append tdnewtable
 
Set dbnewDB = Nothing
 
 
 
End Function

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invalid.jpg
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Comment
Question by:Schuttend
2 Comments
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 50 total points
ID: 22644125
change:

.fields.append.createfield ("Title")

into (not the SPACE between append and .createfield:

.fields.append  .createfield ("Title")  
0
 

Author Closing Comment

by:Schuttend
ID: 31503054
Thanks for the great help!

Regards,
Dennis
0

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