I need a cmd- or bat-script that copies files based on a timeslot.

Posted on 2008-10-05

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Last Modified: 2010-04-21

Hello, I need a cmd or bat script (Windows XP/NT) that copies files based on a timeslot. The audiologging of my radiostation writes files in a directory. The files have a unique name (date and time, example: BNR_20081003_10h00).) Every half our a new file will be written, which is ready after a half hour. When the file is ready (a new file is already busy writing), I want ONLY the latest ready file to be copied to another (network)directory. In other words: the copy of the latest finished file may take place as soon as the file is ready an a new file is being writed. Who can help me with a simple cmd / bat script?

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Question by:PatrickBNR

4 Comments

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Expert Comment

by:AmazingTech

ID: 226531042008-10-06

How were you going to have the script run? Does this folder only has these files? So 1 writing and the others are old logs nothing else? And you want to copy not move these files?

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Accepted Solution

by:AmazingTech

AmazingTech earned 150 total points

ID: 226531692008-10-06

Here's a simple batch file that will skip the 1st newest file in the folder and copy only files that does not already exist in the destination.

Set AudioLogs=C:\AudioLogs
Set NetworkFolder=\\Server\Share
 
FOR /f "skip=1 tokens=*" %%a in ('dir /a-d /o-d /b "%AudioLogs%"') do (
    ECHO XCOPY /d "%AudioLogs%\%%a" "%NetworkFolder%\*.*"
)

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LVL 21

Expert Comment

by:AmazingTech

ID: 226531772008-10-06

Of course you can use a UNC path for the AudioLogs as well.

Set AudioLogs=\\Server\AudioLogs

Remove the ECHO in front of XCOPY for it to copy.

Author Closing Comment

by:PatrickBNR

ID: 315031852008-10-07

Thank you very much! I'm going to try and thinks it's going to work.
Many thanks from Patrick from Holland.

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