Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17


javax.mail.util.SharedByteArrayInputStream error

Posted on 2008-10-06
Medium Priority
Last Modified: 2013-11-23
hi there
i'm trying to get the body of a mimemessage but i get the error javax.mail.util.SharedByteArrayInputStream and i have no idea why it happening

URL url = new URL(sUrl);
InputStream in = url.openStream();
MimeMessage msg  = new MimeMessage(session, in);

String a = msg.getContent().toString();   - I get javax.mail.util.SharedByteArrayInputStream and I have no idea why

Can anyone see what I'm doign wrong.

i've upgraded from java 1.5 to 1.6 and using the latest mail.jar
Question by:csharpperson
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
LVL 23

Expert Comment

ID: 22656545
Getting string from getContent is not a good idea, if you look at javadocs


public java.lang.Object getContent()

    Return the content as a Java object. The type of this object is dependent on the content itself. For example, the native format of a "text/plain" content is usually a String object. The native format for a "multipart" message is always a Multipart subclass. For content types that are unknown to the DataHandler system, an input stream is returned as the content.

    This implementation obtains the content from the DataHandler, that is, it invokes getDataHandler().getContent().

    Specified by:
        getContent in interface Part

        MessagingException - - this is typically thrown by the DataHandler. Refer to the documentation for javax.activation.DataHandler for more details.
    See Also:
        Part, DataHandler.getContent()
LVL 23

Expert Comment

ID: 22656556
You need to change the type of the Content and read the data accordingly

Author Comment

ID: 22657390
could you give me an example of how i do this please?

Author Comment

ID: 22666986
I've solved this myself now ny using getInputStream()


Accepted Solution

Computer101 earned 0 total points
ID: 23061466
PAQed with points refunded (30)

EE Admin

Featured Post

Enroll in September's Course of the Month

This month’s featured course covers 16 hours of training in installation, management, and deployment of VMware vSphere virtualization environments. It's free for Premium Members, Team Accounts, and Qualified Experts!

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

INTRODUCTION Working with files is a moderately common task in Java.  For most projects hard coding the file names, using parameters in configuration files, or using command-line arguments is sufficient.   However, when your application has vi…
Introduction This article is the last of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers our test design approach and then goes through a simple test case example, how …
Viewers learn about the scanner class in this video and are introduced to receiving user input for their programs. Additionally, objects, conditional statements, and loops are used to help reinforce the concepts. Introduce Scanner class: Importing…
This tutorial covers a practical example of lazy loading technique and early loading technique in a Singleton Design Pattern.
Suggested Courses

722 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question