Want to win a PS4? Go Premium and enter to win our High-Tech Treats giveaway. Enter to Win

x
?
Solved

Why isn't my array printing w/in function?

Posted on 2008-10-06
10
Medium Priority
?
200 Views
Last Modified: 2012-05-05
Why isn't my array printing w/in the prinArray function?  It prints if in main, but I need it to reside in a function.  Please help.  Below is my code.


public class yamotdProtocol {
 
	static String[] message = new String[5];
	static Scanner is = null;
	static String m = null;
	private static String line;
	private static String msgget = "MSGGET";
	
	public static void main(String args[]) throws IOException {
	
	try {
		
		is = new Scanner(new FileInputStream("C:\\messages.txt"));
	}
	
	catch(FileNotFoundException e){}
	
	for(int i=0; i<message.length; i++)
	{
		line = is.nextLine();
		message[i] = line;
	}
	
	for(int n =0; n<message.length; n++)
		System.out.println(message[n]);
	}
	
	public void printArray(){
		
		for(int n =0; n<message.length; n++)
			System.out.println(message[n]);
	}
}

Open in new window

0
Comment
Question by:deliachang
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 4
  • 2
10 Comments
 
LVL 24

Expert Comment

by:sciuriware
ID: 22651345
Because 'printArray() is a separate method, that's never called.

;JOOP!
0
 
LVL 8

Accepted Solution

by:
mnrz earned 2000 total points
ID: 22651401
it will, but you have to call that method
check this:


public class yamotdProtocol {
 
        static String[] message = new String[5];
        static Scanner is = null;
        static String m = null;
        private static String line;
        private static String msgget = "MSGGET";
        
        public static void main(String args[]) throws IOException {
        
        try {
                
                is = new Scanner(new FileInputStream("C:\\messages.txt"));
        }
        
        catch(FileNotFoundException e){}
        
        for(int i=0; i<message.length; i++)
        {
                line = is.nextLine();
                message[i] = line;
        }
        
        /*for(int n =0; n<message.length; n++)
                System.out.println(message[n]);
         */
        yamotdProtocol instance = new yamotdProtocol();
        instance.printArray()  ;
        }
        
        public void printArray(){
                
                for(int n =0; n<message.length; n++)
                        System.out.println(message[n]);
        }
}

Open in new window

0
 
LVL 24

Expert Comment

by:sciuriware
ID: 22651409
Change your code to something like this:

public class yamotdProtocol
{
   static String[] message = new String[5];
   static Scanner is = null;
   static String m = null;
   private static String line;
   private static String msgget = "MSGGET";

   public static void main(String args[]) throws IOException
   {
      try
      {
         is = new Scanner(new FileInputStream("C:\\messages.txt"));
      }
      catch(FileNotFoundException e){ /* No action */ }

      for(int i = 0; i < message.length; i++)
      {
         line = is.nextLine();
         message[i] = line;
      }

      for(int n = 0; n < message.length; n++)
         System.out.println(message[n]);
     
      printArray();  // This makes sense!!!!
   }
   
   public static void printArray()
   {

      for(int n = 0; n < message.length; n++)
         System.out.println(message[n]);
   }

}

;JOOP!
0
Industry Leaders: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

 
LVL 8

Expert Comment

by:mnrz
ID: 22651423
or you can declare that method as static:

also please note in Java we don't say function, method is used instead

public static void printArray(){
                
                for(int n =0; n<message.length; n++)
                        System.out.println(message[n]);
        }

Open in new window

0
 
LVL 24

Expert Comment

by:sciuriware
ID: 22651705
I disagree with mnrz: printArray() was embedded inside 'main()'
by bad positioning of { } and it was not called.

;JOOP!
0
 

Author Comment

by:deliachang
ID: 22651749
mnrz, your solution work.  I do have another question and not sure if it can work.  Can I call this function from another class within the same package?

If I declare the an instance of the protocol class in another class, I get nothing but nulls.  Why is this?
public String printArray(String userInput){
		
		String theOutput = userInput;
				
		if (theOutput.equals("MSGGET"))
			theOutput = "It works." + message[0];
		
		return theOutput;
	}

Open in new window

0
 

Author Closing Comment

by:deliachang
ID: 31503472
Thank you so much.  I actually got it working - even calling it from another class.
0
 
LVL 24

Expert Comment

by:sciuriware
ID: 22651948
Thanks deliachang.

;JOOP!
0
 
LVL 8

Expert Comment

by:mnrz
ID: 22652042
sciuriware
no the closing bracket was in right place but the indent was not correct.

deliachang
since the method is declared as public you can call this method from another class but the process in which your message array is populating is placed in main() method and this method is static, so you have to call it before printArray()

check this example out:
 
0
 
LVL 8

Expert Comment

by:mnrz
ID: 22652117
sorry this is example:

public class YourClassName {
 
        String[] message = new String[5];
        Scanner is = null;
        String m = null;
        private String line;
        private String msgget = "MSGGET";
        
        public void populateArray() throws IOException {
        
        try {
                
                is = new Scanner(new FileInputStream("C:\\messages.txt"));
        }
        
        catch(FileNotFoundException e){}
        
        for(int i=0; i<message.length; i++)
        {
                line = is.nextLine();
                message[i] = line;
        }
      }
        
        public void printArray(){
                
                for(int n =0; n<message.length; n++)
                        System.out.println(message[n]);
        }
 
public String printArray(String userInput){
                
                String theOutput = userInput;
                                
                if (theOutput.equals("MSGGET"))
                        theOutput = "It works." + message[0];
                
                return theOutput;
        }
}
 
// in other class
public class AnotherClass {
 
 
        public static void main(String[] a) {
             YourClassName instance = new YourClassName();
             instance.populateArray();
             instance.printArray();
              instance.printArray("MSGGET");
         }
}

Open in new window

0

Featured Post

Important Lessons on Recovering from Petya

In their most recent webinar, Skyport Systems explores ways to isolate and protect critical databases to keep the core of your company safe from harm.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

By the end of 1980s, object oriented programming using languages like C++, Simula69 and ObjectPascal gained momentum. It looked like programmers finally found the perfect language. C++ successfully combined the object oriented principles of Simula w…
Are you developing a Java application and want to create Excel Spreadsheets? You have come to the right place, this article will describe how you can create Excel Spreadsheets from a Java Application. For the purposes of this article, I will be u…
Viewers will learn about arithmetic and Boolean expressions in Java and the logical operators used to create Boolean expressions. We will cover the symbols used for arithmetic expressions and define each logical operator and how to use them in Boole…
This video teaches viewers about errors in exception handling.
Suggested Courses

618 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question