Solved

Code help. Gives balnk page.

Posted on 2008-10-06
11
150 Views
Last Modified: 2013-12-13
What is wrong with this code. Can anyone point out. Thanks
function Input($nama,$com, $id, $all)
{
if($nama == 0){
$com = "<font color=\"red\"> </font>";
 
}
 
$HTML =  
"
<HTML>
	<BODY>
	
	 
		<table width='90%' border='2'> ";
$j = 0;
while($j < $alldata)
{
		
		
$HTML .=  "
  
  
  <tr>
    <td>$id</td>
    <td>$com</td>
  </tr>";
 $j++ 
}  
$HTML .= "</table>
		
	</BODY>
</HTML>";
return $HTML;
}

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Comment
Question by:syedasimmeesaq
  • 6
  • 4
11 Comments
 
LVL 13

Expert Comment

by:compfixer101
ID: 22652234
try this

also what is $j++ for?
<?php
function Input($nama,$com, $id, $all)
{
if($nama == 0){
$com = "<font color=\"red\"> </font>";
 }
 $HTML = "
<HTML>
	<BODY>
		<table width='90%' border='2'> ";
$j = 0;
while($j < $alldata)
{
$HTML .=  "<tr>
    <td>$id</td>
    <td>$com</td>
  </tr>";
 $j++ 
}  
$HTML .= "</table>
	</BODY>
</HTML>";
return $HTML;
}
?>

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LVL 82

Expert Comment

by:hielo
ID: 22652256
change $all:
function Input($nama,$com, $id, $all)

 to $alldata:
function Input($nama,$com, $id, $alldata)
0
 
LVL 9

Author Comment

by:syedasimmeesaq
ID: 22652346
I tried that but the above suggestions didn't work. Still giving me a blank page. I think it is because I am breaking $HTML variable wrong. Any idea ?
Thanks
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LVL 82

Expert Comment

by:hielo
ID: 22652384
you are missing a semicolon after $j++. copy and paste this:
<?php
function Input($nama,$com, $id, $alldata)
{
	if($nama == 0){
		$com = "<font color=\"red\"> </font>";
	}
 
	$HTML ="
<HTML>
        <BODY>
        
         
                <table width='90%' border='2'> ";
$j = 0;
while($j < $alldata)
{
	$HTML .=  "
  <tr>
    <td>{$id}</td>
    <td>{$com}</td>
  </tr>";
 $j++;
}  
$HTML .= "</table>
                
        </BODY>
</HTML>";
return $HTML;
}

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0
 
LVL 9

Author Comment

by:syedasimmeesaq
ID: 22652421
tried that..still no luck
0
 
LVL 82

Expert Comment

by:hielo
ID: 22652474
Did you notice the braces around the variables:
>>   <td>{$id}</td>
>>    <td>{$com}</td>

there's nothing else wrong with that function. Most likely you are not passing the parameters correctly.
0
 
LVL 82

Expert Comment

by:hielo
ID: 22652499
>>$j = 0;
while($j < $alldata)

are you passing a numeric value for $alldata?
0
 
LVL 9

Author Comment

by:syedasimmeesaq
ID: 22652537
yes. What I am trying to do is make the rows of the data from the table. $alldata is 7 cause there are 7 records. the code below works but gives me only 1 record and I want to generate the rows for as many records are there. But when I slice the code below to incoporate WHILE statement, it fails. It doesn't let me break the variable.
Thanks
<?php
function Input($nama,$com, $id, $alldata)
{
	if($nama == 0){
		$com = "<font color=\"red\"> </font>";
	}
 
	$HTML ="
<HTML>
        <BODY>
        
         
                <table width='90%' border='2'> 
	
  <tr>
    <td>{$id}</td>
    <td>{$com}</td>
  </tr>
</table>
                
        </BODY>
</HTML>";
return $HTML;
}

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Accepted Solution

by:
hielo earned 500 total points
ID: 22652773
you probably need $com in between the font tags. The attached code worked for me:
function Input($nama,$com, $id, $alldata)
{
	if($nama == 0){
		$com = "<font color=\"red\">$com</font>";
	}
 
	$HTML ="
<HTML>
        <BODY>
        
         
                <table width='90%' border='2'> ";
$j = 0;
while($j < $alldata)
{
	$HTML .=  "
  <tr>
    <td>{$id}</td>
    <td>{$com}</td>
  </tr>";
 $j++;
}  
$HTML .= "</table>
                
        </BODY>
</HTML>";
return $HTML;
}
 
echo Input(0,"y",3,4);

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LVL 9

Author Comment

by:syedasimmeesaq
ID: 22653146
ok it was my fault..not sending the parameters right. You were right on heilo. Thanks
0
 
LVL 82

Expert Comment

by:hielo
ID: 22653373
you are welcome
0

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