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setting a property that has only a getter

Richard Korts
on
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Last Modified: 2012-05-05
I get the subject error message in FireFox error console.

I believe line 46 is either
ename = document.st.elements[i].name;
or
f2 = ename.substr(0,2);

What does this mean? I don't see a problem.


le = document.st.elements.length;	
			someok = false;
			for (i = 0; i < le; i++) {
				if (document.st.elements[i].type = "hidden") {
					ename = document.st.elements[i].name;
					f2 = ename.substr(0,2);
					if (f2 == "lu") {
						if (document.st.elements[i].value != "None") {
							luval = parseInt(document.st.elements[i].value);
							unitval = parseInt(document.st.selall.value);
							if (luval >= unitval) {
								someok = true;
								break;
							}
						}
					}
				}
			}

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Commented:
make sure your form tag has name="st" AND also make sure every input element has a name defined. If one of your fields does not have a name, this:
ename = document.st.elements[i].name;

will set ename to undefined and cause problems.
Richard KortsBusiness Owner / Chief Developer

Author

Commented:
To hielo:

I gave names to all the elements, including the submit buttons. They were the only ones with no name.

It does the same thing.

Entire html file is attached (note the html is generated from php).
htmlsource.txt
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Richard KortsBusiness Owner / Chief Developer

Author

Commented:
That one gets me EVERY time, in both php & JavaScript. For some reason, I can NEVER see those. So obvious, but so illusive.
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Commented:
>>That one gets me EVERY time
Then it's your responsibility to learn from your mistakes. If you always get something like this wrong:
if( x = 3 )

you will NEVER get it wrong if you invert them:
if( 3 = x )

a number and a string are "constants". You cannot assign something to a constant, so the compiler/interpreter will throw a runtime error if you omit that second = sign. At that point its obvious.

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