?
Solved

Sql Syntax

Posted on 2008-10-06
1
Medium Priority
?
299 Views
Last Modified: 2012-05-05
Hello, I need to alter this portion:

                Select count(LinkID) as Clicks, LinkID
                from OutboundTraffic
                group by LinkID

of the sql query i have below so that I can do a count of all records with the correct LinkID (as it does now) and also get a count of all records with the correct LinkID with a OutboundTraffic.ClickDate value = to todays date.  Im not sure of the syntax required to make this work.

Thanks
SELECT
        l.LinkID,
        l.NavigateURL,
        l.ImageFile,
        l.Status,
        isnull(l.StartDate, GetDate()) As StartDate,
        isnull(u.rating,0) AS Rating,
        isnull(o.Clicks,0) AS Clicks
FROM LinkIndex l
left join ( 
                Select sum(rating) as Rating, LinkID
                from UserRatings 
                group by LinkID
        ) u
on l.LinkID = u.LinkID
left join ( 
                Select count(LinkID) as Clicks, LinkID
                from OutboundTraffic
                group by LinkID
        ) o
on l.LinkId = o.LinkId
where status in (0,1,2) and userid = 1001
order by startdate

Open in new window

0
Comment
Question by:grogo21
1 Comment
 
LVL 61

Accepted Solution

by:
Kevin Cross earned 2000 total points
ID: 22656301
You can modify like this:
Select count(LinkID) as Clicks, LinkID
                , SUM(Case DateDiff(dd, ClickDate, getdate()) When 0 Then 1 Else 0 End) AS TodaysClicks
                from OutboundTraffic
                group by LinkID

Using a case when to generate a 1 or 0 for records matching criteria and then use SUM to simulate a count of the 1's should do the trick.

SELECT
        l.LinkID,
        l.NavigateURL,
        l.ImageFile,
        l.Status,
        isnull(l.StartDate, GetDate()) As StartDate,
        isnull(u.rating,0) AS Rating,
        isnull(o.Clicks,0) AS Clicks,
        isnull(o.TodaysClicks,0) AS TodaysClicks
FROM LinkIndex l
left join ( 
                Select sum(rating) as Rating, LinkID
                from UserRatings 
                group by LinkID
        ) u
on l.LinkID = u.LinkID
left join ( 
                Select count(LinkID) as Clicks, LinkID
                , SUM(Case DateDiff(dd, ClickDate, getdate()) When 0 Then 1 Else 0 End) AS TodaysClicks
                from OutboundTraffic
                group by LinkID
        ) o
on l.LinkId = o.LinkId
where status in (0,1,2) and userid = 1001
order by startdate

Open in new window

0

Featured Post

Concerto Cloud for Software Providers & ISVs

Can Concerto Cloud Services help you focus on evolving your application offerings, while delivering the best cloud experience to your customers? From DevOps to revenue models and customer support, the answer is yes!

Learn how Concerto can help you.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Recursive SQL is one of the most fascinating and powerful and yet dangerous feature offered in many modern databases today using a Common Table Expression (CTE) first introduced in the ANSI SQL 99 standard. The first implementations of CTE began ap…
MSSQL DB-maintenance also needs implementation of multiple activities. However, unprecedented errors can hamper the database management. In that case, deploying Stellar SQL Database Toolkit ensures fast and accurate database and backup repair as wel…
Is your data getting by on basic protection measures? In today’s climate of debilitating malware and ransomware—like WannaCry—that may not be enough. You need to establish more than basics, like a recovery plan that protects both data and endpoints.…
With just a little bit of  SQL and VBA, many doors open to cool things like synchronize a list box to display data relevant to other information on a form.  If you have never written code or looked at an SQL statement before, no problem! ...  give i…

571 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question