Solved
subnet this network with ip address 192.168.147.0
Posted on 2008-10-07
Hey everyone,
I am studying again for my ccna exam and want to recertify so i can start my ccnp eventually but im having a little trouble subnetting even though i understand it pretty good. I know 128, 192, 224, 240, 248, 252, 254. I know 128 has 1 bit turned on and 7 bits turned off, 192 has 2 bits turned on and 6 bits turned off, etc. The on's are 1s and bits turned off are 0s which is host. For example 192.168.1.128 /26, where /26 is 255.255.255.192. well 256-192=64, so 0 64 128, 192, 256, so 128 would fall in between 128 and 192. 192 would be the next subnet. 191 would be broadcast and 190 would be last usable host. Okay so now here is a picture of a full network that i need to subnet using ip address 192.168.147.0. I have to figure out what subnet to use and i am not sure. I know /27 would give 8 subnets and 30 hosts so im not sure if that would work. Can someone please explain this better to me.
thanks