XML Formatting

Try to use an identity transformation, it should output with line breaks, especially if you use <xsl:output> with the indent="yes" attribute

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" indent="yes" encoding="iso-8859-1"/>
 
	<xsl:template match="@*|node()">
	  <xsl:copy>
	    <xsl:apply-templates select="@*|node()"/>
	  </xsl:copy>
	</xsl:template>	
</xsl:stylesheet>

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I'm a little confused.

Here, let me show you the XSLT stylesheet we're already using.
I have the indent="yes" in there and it fails to do that.

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" indent="yes" media-type="text/xml" omit-xml-declaration="no" version="1.0"/>
	<xsl:template match="/" xmlns:addData="http://www.abbyy.com/FlexiCapture/Schemas/Export/AdditionalFormData.xsd"
	xmlns:form="http://www.abbyy.com/FlexiCapture/Schemas/Export/FormData.xsd">
		<document xmlns="http://www.ademero.com/XmlSchemas/ContentCentral/XmlCaptureDescriptorV1.1">
			<electronicFile>
				<xsl:value-of select="form:Documents/*/@addData:ImagePath" />
			</electronicFile>
			<destination>
				<catalog documentType="default">Accounts Payable</catalog>
			</destination>
			<fields>
				<field name="Invoice">
					<xsl:value-of select="form:Documents/*/_Document/_Invoice" />
				</field>
				<field name="Vendor">
					<xsl:value-of select="form:Documents/*/_Document/_Vendor" />
				</field>
				<field name="Date">
					<xsl:value-of select="form:Documents/*/_Document/_Date" />
				</field>
			</fields>
		</document>
	</xsl:template>
</xsl:stylesheet>

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May I ask you what the xsl processor are you using?
I tried on MSXML v3 and v6, it does obey the indent attribute.

I'm using a simple Xsl.Transform command in Microsoft C# version 3.5

I'm not familiar with how to use MSXML v6, I've just written a little program in C# that does the transform.

Did you make changes to the XSLT that I posted to make it do that? I'm trying again and I'm just not able to get it to format the document. I'm extremely new to working with XML, and they've put me on a very short deadline, so I haven't had the chance to read a lot of what I would have if I had been granted more time on this project.

You don't need a complex xslt to just reformat the xml with the same structure it already has.
All you need is a copy xslt which I have provided you in the first comment.

I tried to use the xsl from a C# program, and you right it does ignore the indent="yes" attribute.

Try to use the copy xsl with the following command line utility, it uses MSXML v3 as far as I know.
http://www.microsoft.com/downloads/details.aspx?FamilyID=2fb55371-c94e-4373-b0e9-db4816552e41&DisplayLang=en

Well, this isn't the original document. The XSLT transforms it from a different document.

The reason I use the C# tool is because I have to execute this on a couple hundred thousand documents.

Thanks, using all of this I was able to design a working solution. I appreciate it!