VBA: getting part of string

I have the following string..it always varies in length.. Up to the ":" is consistant and the period after each line.  How to extract number out of string for each line...thanks..

Have several lines.  The below is an example.  

This is my first line  :      234.
This is my second line   :      100.
TechMonsterAsked:
Who is Participating?
 
Patrick MatthewsConnect With a Mentor Commented:
Sorry, misunderstood.  Add the UDF below, and then use this expression to return the numbers in a
zero based array:

Dim arr As Variant

arr = RegExpFind(SomeVariable, "\d+")


Function RegExpFind(LookIn As String, PatternStr As String, Optional Pos, _
    Optional MatchCase As Boolean = True) 
    ' For more info see: http://vbaexpress.com/kb/getarticle.php?kb_id=841 
    ' This function uses Regular Expressions to parse a string (LookIn), and return matches to a
    ' pattern (PatternStr).  Use Pos to indicate which match you want:
    ' Pos omitted               : function returns a zero-based array of all matches
    ' Pos = 0                   : the last match
    ' Pos = 1                   : the first match
    ' Pos = 2                   : the second match
    ' Pos = <positive integer>  : the Nth match
    ' If Pos is greater than the number of matches, is negative, or is non-numeric, the function
    ' returns an empty string.  If no match is found, the function returns an empty string
    
    ' If MatchCase is omitted or True (default for RegExp) then the Pattern must match case (and
    ' thus you may have to use [a-zA-Z] instead of just [a-z] or [A-Z]).
    
    ' If you use this function in Excel, you can use range references for any of the arguments.
    ' If you use this in Excel and return the full array, make sure to set up the formula as an
    ' array formula.  If you need the array formula to go down a column, use TRANSPOSE()
    
    Dim RegX As Object
    Dim TheMatches As Object
    Dim Answer() As String
    Dim Counter As Long
    
    ' Evaluate Pos.  If it is there, it must be numeric and converted to Long
    If Not IsMissing(Pos) Then
        If Not IsNumeric(Pos) Then
            RegExpFind = ""
            Exit Function
        Else
            Pos = CLng(Pos)
        End If
    End If
    
    ' Create instance of RegExp object
    Set RegX = CreateObject("VBScript.RegExp")
    With RegX
        .Pattern = PatternStr
        .Global = True
        .IgnoreCase = Not MatchCase
    End With
        
    ' Test to see if there are any matches
    If RegX.test(LookIn) Then
        
        ' Run RegExp to get the matches, which are returned as a zero-based collection
        Set TheMatches = RegX.Execute(LookIn)
        
        ' If Pos is missing, user wants array of all matches.  Build it and assign it as the
        ' function's return value
        If IsMissing(Pos) Then
            ReDim Answer(0 To TheMatches.Count - 1) As String
            For Counter = 0 To UBound(Answer)
                Answer(Counter) = TheMatches(Counter)
            Next
            RegExpFind = Answer
        
        ' User wanted the Nth match (or last match, if Pos = 0).  Get the Nth value, if possible
        Else
            Select Case Pos
                Case 0                          ' Last match
                    RegExpFind = TheMatches(TheMatches.Count - 1)
                Case 1 To TheMatches.Count      ' Nth match
                    RegExpFind = TheMatches(Pos - 1)
                Case Else                       ' Invalid item number
                    RegExpFind = ""
            End Select
        End If
    
    ' If there are no matches, return empty string
    Else
        RegExpFind = ""
    End If
    
    ' Release object variables
    Set RegX = Nothing
    Set TheMatches = Nothing
    
End Function

Open in new window

0
 
Patrick MatthewsCommented:
Debug.Print Trim(Split(SomeVariable, ":")(1))
0
 
TechMonsterAuthor Commented:
It almost works.  i see the number with the period. but also the following line.
So I get this

 234.
This is my second line  
0
Cloud Class® Course: SQL Server Core 2016

This course will introduce you to SQL Server Core 2016, as well as teach you about SSMS, data tools, installation, server configuration, using Management Studio, and writing and executing queries.

 
Jaime OlivaresSoftware ArchitectCommented:
For VBA I would use:
Dim sample as String
Dim value as String
Dim colon as Integer

colon = Instr(, sample, ":")
sample = "This is my first line  :      234."
value = val(Mid(sample, colon+1, Instr(colon, sample, ".") - colon))
0
 
fabriciofonsecaCommented:
Based on matthewspatrick code you can do:

Cint(Trim(Split("This is my first line  :      234.", ":")(1)))


Regards
0
 
Patrick MatthewsCommented:
TechMonster,

Just to confirm, are they two separate strings, or is it one string with multiple lines?

Regards,

Patrick
0
 
Jaime OlivaresSoftware ArchitectCommented:
Oops, in my sample code, there is an error in line ordering, should be:

Dim sample as String
Dim value as String
Dim colon as Integer

sample = "This is my first line  :      234."
colon = Instr(, sample, ":")
value = val(Mid(sample, colon+1, Instr(colon, sample, ".") - colon))

the real job is made in the last 2 lines
0
 
TechMonsterAuthor Commented:
One string.  
0
 
TechMonsterAuthor Commented:
I was kinda prone to the original idea.
I think the method would work if the starting could be ":" and the end point is "."

So just need to get data between the : and the .  

Thanks.
 
0
 
Patrick MatthewsCommented:
TechMonster said:
>>I was kinda prone to the original idea.

Did you try my 2nd attempt, with the UDF?
0
 
TechMonsterAuthor Commented:
Not yet..working on it...
0
 
TechMonsterAuthor Commented:
Ok,,,I've got it... I am just repeating this for each line....changing the the inStr each time..

Thanks.

idx = InStr(s, "This is my first line    :")
    result = Mid(s, idx, l - idx)
    colPos = (InStr(result, ":") + 1)
    perPos = InStr(result, ".")
    dataLen = (perPos - colPos)
    result= Mid(result, colPos, dataLen)
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.