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Need a workaround for execdir on system with old find

Posted on 2008-10-09
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Last Modified: 2013-12-16
I need a workaround for execdir on system with an old version of the find command.  Here's the command I tried:

find . -type d -name 'crmngp' -execdir cvs up -C -r DRUPAL-5

How can I replicate that on a system with no execdir support?
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Question by:seanr1978
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Expert Comment

by:Tintin
ID: 22682605
find . -type d -name 'crmngp' -exec cvs up -C -r DRUPAL-5 {} \;
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Author Comment

by:seanr1978
ID: 22682631
Fails because it can't find the CVSROOT without first changing to the directory (hence the need for execdir):

cvs update: No CVSROOT specified!  Please use the `-d' option
cvs [update aborted]: or set the CVSROOT environment variable.
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Author Comment

by:seanr1978
ID: 22682639
BTW, if this needs to be done as a perl script or something like that, I'm perfectly OK with that - I just need it to work. ;-)
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Accepted Solution

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Tintin earned 500 total points
ID: 22683144
You could do
#!/bin/bash
here=`pwd`
find . -type d -name 'crmngp' | while read dir
do
  cd $here/$dir
  cvs up -C -r DRUPAL -5
done

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Author Comment

by:seanr1978
ID: 22687301
That generates ": bad interpreter: No such file or directory"
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Author Comment

by:seanr1978
ID: 22687515
Nevermind, figured that one out, and got it to work in a shell script.  Now I'd like to go one further and add it to a function I already had in my .bashrc.  You'll see below that if I call the function as "dg -r crmngp 5", it'll run the first part (based on the code you supplied), print a copy of the find command it uses and it should work through the directories and update them.  The problem, though, is it doesn't ever get into the while part (as if it found no results).  Here's the find command it prints in that echo statement:

find /www/drupal5.ngphost.com -type d -name 'crmngp'

That is correct and there are two copies of crmngp under that directory (one in html/modules and the other in html/new/modules).  Why does it find them when I run that find command normally from the command line but not from within the function in .bashrc?
function dg() {
  if [ "$1" = "-r" ]; then
    here=`pwd`
    echo "find $here -type d -name '$2'"
    find $here -type d -name '$2' | while read dir
    do
      echo "updating $here/$dir"
      cd $here/$dir
      cvs up -C -r DRUPAL-$3
    done
  else
    if [ "$1" = "drupal" ]; then
      if [ -z "$2" ]; then
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal checkout -d ./ drupal;
      else
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal checkout -r DRUPAL-$2 -d ./ drupal;
      fi
    else
      if [ -z "$2" ]; then
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal-contrib checkout -d $1 contributions/modules/$1;
      else
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal-contrib checkout -r DRUPAL-$2 -d $1 contributions/modules/$1;
      fi
    fi
  fi
}

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Author Comment

by:seanr1978
ID: 22688537
Got it with some help in #bash on irc.freenode.net:
function dg() {
  if [ "$1" = "-r" ]; then
    here=`pwd`
    echo "find $here -type d -name '$2'"
    find $here -type d -name "$2" | while read dir
    do
      echo "updating $dir"
      cd $dir
      cvs up -C -r DRUPAL-$3
    done
  else
    if [ "$1" = "drupal" ]; then
      if [ -z "$2" ]; then
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal checkout -d ./ drupal;
      else
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal checkout -r DRUPAL-$2 -d ./ drupal;
      fi
    else
      if [ -z "$2" ]; then
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal-contrib checkout -d $1 contributions/modules/$1;
      else
        cvs -z6 -d:pserver:anonymous:anonymous\@cvs.drupal.org:/cvs/drupal-contrib checkout -r DRUPAL-$2 -d $1 contributions/modules/$1;
      fi
    fi
  fi
}

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Author Closing Comment

by:seanr1978
ID: 31504839
Thank you very much!
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