kuntilanak
asked on
context free grammar
can someone give me a link in the internet of resources that proves :
L = {a^nba^mba^(m+n) | n,m>=1}
L = {a^nba^mba^(m+n) | n,m>=1}
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M ::= b | a M a
L ::= b M | a L a'
L ::= b M | a L a'
ASKER