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Join requires all to exist

Posted on 2008-10-10
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Last Modified: 2013-11-05
I have a tricky JOIN problem.
My stored procedure takes a xml in-parameter in which all rows together forms an unique identity. The number of rows is dynamic, e.g., there could be one row, two rows or even three rows that makes up the identity.
Example xml:
<ROOT>
<SourceItem ItemValue="S1IV1" SequenceNo="1"/>
<SourceItem ItemValue="S1IV2" SequenceNo="2"/>
<SourceItem ItemValue="S1IV3" SequenceNo="3"/>
</ROOT>

The corresponding table defining the identity looks as this:

CREATE TABLE [dbo].[MappingSourceItem](
      [MappingSourceItemID] [int] IDENTITY(1,1) NOT NULL,
      [MappingSourceID] [int] NOT NULL,
      [ItemValue] [varchar](200) NOT NULL,
      [SequenceNo] [int] NOT NULL
) ON [PRIMARY]

with the content
MappingSourceItemID MappingSourceID ItemValue SequenceNo
106; 43; S1IV1; 1
107; 43; S1IV2; 2
108; 43; S1IV3; 3
109; 44; S1IV1; 1
110; 44; S1IV2; 2

I then want to find out if the identity given in the example xml exists in the database.
As you can see it does for MappingSourceID=43 since all three rows in the xml mathes.
For MappingSourceID=44 it does not match since only the two first match. How do I write such a join where all rows must match?
My attempt below does not work since it returns all rows matching and does not care that all of them dont match.
DECLARE @Source varchar(MAX)
SET @Source = '<ROOT><SourceItem ItemValue="S1IV1" SequenceNo="1"/><SourceItem ItemValue="S1IV2" SequenceNo="2"/><SourceItem ItemValue="S1IV3" SequenceNo="3"/></ROOT>'

DECLARE @DocHandleSource int

EXEC sp_xml_preparedocument @DocHandleSource OUTPUT, @Source      

SELECT * FROM MappingSourceItem AS msi
JOIN OPENXML (@DocHandleSource, '/ROOT/SourceItem',1)
WITH (ItemValue  varchar(200), SequenceNo int) AS s
ON msi.ItemValue = s.ItemValue AND msi.SequenceNo = s.SequenceNo
WHERE msi.MappingSourceID = 44

will return the two rows for MappingSourceID=44 but I want it to return 0 rows since not all match.

0
Comment
Question by:gnidde1967
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5 Comments
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 22685336
use LEFT JOIN instead of JOIN
0
 

Author Comment

by:gnidde1967
ID: 22685384
No, that doesn't work.

Run the following script and you see that the two rows for MappingSourceID=44 will be returned and that is not desired. I want 0 rows to be returned.

IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[MappingSourceItem]') AND type in (N'U'))
DROP TABLE [dbo].[MappingSourceItem]

GO

CREATE TABLE [dbo].[MappingSourceItem](
      [MappingSourceItemID] [int] IDENTITY(1,1) NOT NULL,
      [MappingSourceID] [int] NOT NULL,
      [ItemValue] [varchar](200) NOT NULL,
      [SequenceNo] [int] NOT NULL
) ON [PRIMARY]

GO

INSERT INTO MappingSourceItem ( MappingSourceItemID, MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV1',  1);
INSERT INTO MappingSourceItem ( MappingSourceItemID, MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV2',  2);
INSERT INTO MappingSourceItem ( MappingSourceItemID, MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV3',  3);
INSERT INTO MappingSourceItem ( MappingSourceItemID, MappingSourceID, ItemValue, SequenceNo ) VALUES (44 , 'S1IV1',  1);
INSERT INTO MappingSourceItem ( MappingSourceItemID, MappingSourceID, ItemValue, SequenceNo ) VALUES (44 , 'S1IV2',  2);

DECLARE @Source varchar(MAX)
SET @Source = '<ROOT><SourceItem ItemValue="S1IV1" SequenceNo="1"/><SourceItem ItemValue="S1IV2" SequenceNo="2"/><SourceItem ItemValue="S1IV3" SequenceNo="3"/></ROOT>'

DECLARE @DocHandleSource int

EXEC sp_xml_preparedocument @DocHandleSource OUTPUT, @Source      

SELECT * FROM MappingSourceItem AS msi
LEFT JOIN OPENXML (@DocHandleSource, '/ROOT/SourceItem',1)
WITH (ItemValue  varchar(200), SequenceNo int) AS s
ON msi.ItemValue = s.ItemValue AND msi.SequenceNo = s.SequenceNo
WHERE msi.MappingSourceID = 44

0
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 22685455
ok, I see:
GO
 
CREATE TABLE [dbo].[MappingSourceItem](
      [MappingSourceItemID] [int] IDENTITY(1,1) NOT NULL,
      [MappingSourceID] [int] NOT NULL,
      [ItemValue] [varchar](200) NOT NULL,
      [SequenceNo] [int] NOT NULL
) ON [PRIMARY]
 
GO
 
INSERT INTO MappingSourceItem ( MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV1',  1);
INSERT INTO MappingSourceItem ( MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV2',  2);
INSERT INTO MappingSourceItem ( MappingSourceID, ItemValue, SequenceNo ) VALUES (43 , 'S1IV3',  3);
INSERT INTO MappingSourceItem ( MappingSourceID, ItemValue, SequenceNo ) VALUES (44 , 'S1IV1',  1);
INSERT INTO MappingSourceItem ( MappingSourceID, ItemValue, SequenceNo ) VALUES (44 , 'S1IV2',  2);
 
DECLARE @Source varchar(8000)
SET @Source = '<ROOT>
<SourceItem ItemValue="S1IV1" SequenceNo="1"/>
<SourceItem ItemValue="S1IV2" SequenceNo="2"/>
<SourceItem ItemValue="S1IV3" SequenceNo="3"/>
</ROOT>'
 
DECLARE @DocHandleSource int
 
EXEC sp_xml_preparedocument @DocHandleSource OUTPUT, @Source      
 
declare @mid int
set @mid = 43
 
;WITH s as (
  SELECT * FROM OPENXML (@DocHandleSource, '/ROOT/SourceItem',1)
   WITH (ItemValue  varchar(200), SequenceNo int) AS s
)
SELECT * 
  FROM s 
  JOIN MappingSourceItem AS msi
    ON msi.ItemValue = s.ItemValue 
   AND msi.SequenceNo = s.SequenceNo
   AND msi.MappingSourceID = @mid 
  WHERE NOT EXISTS ( select null 
                       from s 
                       left JOIN MappingSourceItem AS msi
                         ON msi.ItemValue = s.ItemValue 
                        AND msi.SequenceNo = s.SequenceNo
                        AND msi.MappingSourceID = @mid 
                       where msi.MappingSourceID is null
                     )
go
DROP TABLE [dbo].[MappingSourceItem]

Open in new window

0
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 22685456
change:
set @mid = 43
to this:
set @mid = 44

to test with indeed 0 rows returned.
0
 

Author Comment

by:gnidde1967
ID: 22685645
Thanks angelIII,

Nice solution!
0

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