Solved

# pull numeric beginning part of a column value, ignore letters, sort on the results

Posted on 2008-10-10
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Values of column "acreage":

5
10
20
1 to 5
3 to 8

I want to numeric sort on either the number (in the case of the first three), or the first number (case of last two). So ignore the " to 5" and " to 8", but otherwise it would be convert (int, acreage). How can I do this?

Thank you!
0
Question by:bbdesign
• 3
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LVL 60

Expert Comment

declare @x varchar(max)
set @x = '3'

select left(@x, case when charindex(' ', @x) = 0 then len(@x) else charindex(' ', @x) end)

so, for a table:

select left(fieldname, case when charindex(' ', fieldname) = 0 then len(fieldname) else charindex(' ', fieldname) end)
from table
0

LVL 60

Expert Comment

then just throw your cast around that value:

select cast(left(fieldname, case when charindex(' ', fieldname) = 0 then len(fieldname) else charindex(' ', fieldname) end) as int)
from table
0

LVL 92

Expert Comment

Assuming your column *always* starts with at least one numeral...

SELECT *
FROM SomeTable
ORDER BY CAST(LEFT(LEFT(acreage, PATINDEX('%[^0-9]%', acreage) - 1), 3) AS int)
0

Author Comment

chapmandew: I'm trying to put this in an "order by" claus, not a select.

matthewspatrick: I get this error: "Invalid length parameter passed to the SUBSTRING function"

The column always starts with at least one numeral. Sometimes there are other characters (i.e., spaces and/or letters) after the numeral (which can be any number of characters in length), sometimes not.
0

LVL 60

Accepted Solution

chapmandew earned 250 total points
select *
from table
order by cast(left(fieldname, case when charindex(' ', fieldname) = 0 then len(fieldname) else charindex(' ', fieldname) end) as int)
0

LVL 92

Assisted Solution

Patrick Matthews earned 250 total points
SELECT *
FROM SomeTable
ORDER BY CAST(LEFT(LEFT(acreage, CASE WHEN PATINDEX('%[^0-9]%', acreage) > 0 THEN (PATINDEX('%[^0-9]%', acreage) - 1) ELSE LEN(acreage) END), 3) AS int)
0

Author Comment

Thanks!
0

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