How to I replace a block of text while specifying start and end tags and a replacement string?

Posted on 2008-10-12
Last Modified: 2013-12-13
I need to replace a block of text e.g.


this is some
text which
I want to remove


With some some other text e.g.

new text

So the result should be...

new text

I would expect the function to work like this

$result = str_replace_func($my_text, "<start-tag>", "<end-tag">, "new text");

Question by:mindwarpltd
  • 3
  • 2

Expert Comment

by:Sander Stad
ID: 22700778
The str_replace function does not look between strings but searches for strings that are given. You could use the code I added.
What is does is it gets a variable with the text it has to search. Than a pattern is made, you could make this dynamic with variables in a function. Than the content what will replace the old.
At last the preg_replace function calls all teh three variables and replaces the text.

$p = '<style type="text/css"> css css css</style>'; 

$pattern = "/<style\b[^>]*>(.*?)<\/style>/ims"; 

$content = "test"; 

echo preg_replace($pattern, $content, $p); 

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Author Comment

ID: 22700817
I'm a little confused by the pattern. Can you show me what my pattern would look like?

Accepted Solution

Sander Stad earned 500 total points
ID: 22700883
It would look like this:

$p = '<start-tag>this is some text i want to remove</end-tag>'; 

$pattern = "/<sart-tag\b[^>]*>(.*?)<\/end-tag>/ims"; 

$content = "new text"; 

echo preg_replace($pattern, $content, $p); 

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Author Comment

ID: 22701089

I had to change the start and end tags...
I have...

$pattern = "/<!-- Start Foot Ad --\b[^>]*>(.*?)<!-- End Foot Ad -->/ims";

<!-- Start Foot Ad -->
<!-- End Foot Ad -->


Author Comment

ID: 22701729
I've worked out the answer.

$pattern = "/<!--StartFootAd-->(.*?)<!--EndFootAd-->/ims";

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