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Formatting print_r($_FILES)

Hi guys,
Im working on php upload stuff at the moment, and was wondering if there is a nice way of displaying in a browser all the key value pairs for a $_FILES array.
At the moment, im just doing the following..

print_r($_FILES);

which gives me a bit of a messy output..

Array ( [userfile] => Array ( [name] => Array ( [0] => tooltipdb_0000003.jpg [1] => [2] => [3] => ) [type] => Array ( [0] => image/pjpeg [1] => [2] => [3] => ) [tmp_name] => Array ( [0] => c:/wamp/tmp\php14B2.tmp [1] => [2] => [3] => ) [error] => Array ( [0] => 0 [1] => 4 [2] => 4 [3] => 4 ) [size] => Array ( [0] => 333635 [1] => 0 [2] => 0 [3] => 0 ) ) )

Any help on formatting this output much appreciated.
0
Simon336697
Asked:
Simon336697
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2 Solutions
 
hampus_bCommented:
add <pre> before and </pre> after and it will be readable.

But to take control over the output; do like this:


<?
 
foreach ($array AS $key => $value) {
 echo "<strong>$key</strong>";
 echo "<br />";
echo $value;
echo "<br />"
}
 
?>

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ChorchCommented:
hello,

try this:

<?php
function echo_array($array,$return_me){
    if(is_array($array) == false){
        $return = "The provided variable is not an array.";
    }else{
        foreach($array as $name=>$value){
            if(is_array($value)){
                $return .= "";
                $return .= "['<b>$name</b>'] {<div style='margin-left:10px;'>\n";
                $return .= echo_array($value,true);
                $return .= "</div>}";
                $return .= "\n\n";
            }else{
                if(is_string($value)){
                    $value = "\"$value\"";
                }
                $return .= "['<b>$name</b>'] = $value\n\n";
            }
        }
    }
    if($return_me == true){
        return $return;
    }else{
        echo "<pre>".$return."</pre>";
    }
}

echo_array($_FILES, 'false');
?>

Regards
0
 
hampus_bCommented:
i mean like this:
echo "<pre>";
print_r($_FILES);
echo "</pre>";

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Simon336697Author Commented:
Hi Chorch,
Thanks so much for spending the time on this.
I ran this but it does not return any output at all.
That is, it doesnt return if it is not an array eg.
$return = "The provided variable is not an array.";
0
 
Simon336697Author Commented:
My mistake...you guys are the best...all is good Chorch...it works..
Thanks Chorch very much and hampus_b:
0
 
ChorchCommented:
Thanks, glad to see I helped you!
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