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# Query Problem With DatePart

Posted on 2008-10-13
Medium Priority
219 Views
Hello,
I am attempting to filter my CaseNumber column (Text) by the first 2 digits by using the following SQL query and I keep getting an error.

SELECT     MAX(Mid(CaseNumber, 3, 6)) AS CaseValue
FROM         ServiceCalls
WHERE     (LEFT(CaseNumber, 2) = DatePart(yy, NOW()))
0
Question by:Gunit2507
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Accepted Solution

PaulKeating earned 2000 total points
ID: 22707110
LEFT() returns a string. DATEPART() returns an integer. I guess the message you are getting says "implicit conversion..."

Furthermore, DATEPART(yy ... ) returns a 4-digit year, not a 2-digit year as you seem to think: year and yyyy and yy  all mean the same thing.

GROUP BY CONVERT(INT, LEFT(CaseNumber, 2))
HAVING      CONVERT(INT(LEFT(CaseNumber, 2)) = (DatePart(yy, NOW())) % 100)

0

LVL 5

Assisted Solution

PaulKeating earned 2000 total points
ID: 22707136
Unmatched parens: fix is

GROUP BY CONVERT(INT, LEFT(CaseNumber, 2))
HAVING      CONVERT(INT, LEFT(CaseNumber, 2)) = (DatePart(yy, NOW()) % 100)
0

Author Comment

ID: 22707228
This seems to work:

SELECT     MAX(Mid(CaseNumber, 3, 6)) AS CaseValue
FROM         ServiceCalls
WHERE     (LEFT(CaseNumber, 2) = RIGHT(DatePart('yyyy', NOW()), 2))
0

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