DateAdd for business days or calendar days which ever is greater

capricorn1 was able to help with the below answer.  I have another question that is a bit more complex.  My original question was how to create a module and expression to calculate business days.  

The answer is:

"place this codes in  a module

Function getDeadLineDate(dDate As Date, Span As Integer) As Date
Dim j As Integer, i As Integer, dtStart
dtStart = dDate
For j = 1 To Span
    dtStart = dtStart + 1
    Do While Weekday(dtStart) = 1 Or Weekday(dtStart) = 7 '_
        dtStart = dtStart + 1
        i = i + 1
    Loop
Next
getDeadLineDate = DateAdd("d", i + Span, dDate)

End Function

to use

If [State or Federal Mandates_ID] = 4 And [Review Level_ID] = 2 Then
    [Determination Compliance Deadline D/T] = getDeadLineDate([Request D/T],2)
End If"

I have another question...  I want to use a similar expression to decide to use "which ever is greater" when it comes to business days or calendar days.  I need a formula that calculates either 1 business day or 72 hours which ever is greater.  This seems to only be a problem on Fridays.  I need it to use 1 business day if it is Friday otherwise use 72 hours.

Thanks for the help!
dddwAsked:
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Gustav BrockConnect With a Mentor CIOCommented:
> I need it to use 1 business day if it is Friday otherwise use 72 hours.

But if it is Thursday that would return Sunday. Probably not what you want.

Your next question will probably be how to skip a juxtaposed holiday. So, what you can do is to use the functions below like this:

datToday = Date
datNext = DateSkipNonWorkingday(DateAdd("d", 3, datToday))

This way datToday can be any weekday - including weekend - while datNext will be at least three days later skipping any weekend day or holiday.

/gustav
Public Function DateSkipNoneWorkingday( _
  ByVal datDate As Date, _
  Optional ByVal booReverse As Boolean) _
  As Date
 
' Purpose: Calculate first working day following/preceding datDate.
'
' May be freely used and distributed.
' 1999-07-03, Cactus Data ApS, CPH
  
  Dim datNext As Date
  Dim datTest As Date
    
  datNext = datDate
  Do
    datTest = datNext
    datNext = DateSkipHoliday(datTest, booReverse)
    datNext = DateSkipWeekend(datNext, booReverse)
  Loop Until DateDiff("d", datTest, datNext) = 0
  
  DateSkipNoneWorkingday = datNext
 
End Function
 
Public Function DateSkipWeekend( _
  ByVal datDate As Date, _
  Optional ByVal booReverse As Boolean) _
  As Date
 
' Purpose: Calculate first working day equal to or following/preceding datDate.
' Assumes: 5 or 6 working days per week. Weekend is (Saturday and) Sunday.
' Limitation: Does not count for public holidays.
'
' May be freely used and distributed.
' 1999-07-03, Cactus Data ApS, CPH
  
  Const cintWorkdaysOfWeek As Integer = 5
 
  Dim bytSunday   As Byte
  Dim bytWeekday  As Byte
  
  bytSunday = WeekDay(vbSunday, vbMonday)
  bytWeekday = WeekDay(datDate, vbMonday)
  
  If bytWeekday > cintWorkdaysOfWeek Then
    ' Weekend.
    If booReverse = False Then
      ' Get following workday.
      datDate = DateAdd("d", 1 + bytSunday - bytWeekday, datDate)
    Else
      ' Get preceding workday.
      datDate = DateAdd("d", cintWorkdaysOfWeek - bytWeekday, datDate)
    End If
  End If
 
  DateSkipWeekend = datDate
 
End Function
 
Public Function DateSkipHoliday( _
  ByVal datDate As Date, _
  Optional ByVal booReverse As Boolean) _
  As Date
 
' Purpose: Calculate first day following/preceding datDate if this is holiday.
'
' May be freely used and distributed.
' 1999-07-03, Cactus Data ApS, CPH
  
  ' Adjust to fit your table of holidays.
  Const cstrHolidayTable  As String = "tblHoliday"
  Const cstrHolidayField  As String = "HolidayDate"
  
  While Not IsNull(DLookup(cstrHolidayField, cstrHolidayTable, cstrHolidayField & " = " & Format(datDate, "\#m\/d\/yyyy\#")))
    datDate = DateAdd("d", 1 - Abs(2 * booReverse), datDate)
  Wend
 
  DateSkipHoliday = datDate
 
End Function

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Rey Obrero (Capricorn1)Commented:
define how 1 business day can be greater then 72 hours and vice versa.
0
 
dddwAuthor Commented:
Thank you!
0
 
Gustav BrockCIOCommented:
You are welcome!

/gustav
0
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