Convert VARCHAR value to DATETIME

OK in SQL in a column called "STARTDATE" I a list of values that don't really show DATETIME. I need to convert...

20081018090000 which is 2008= year, 10 = month, 18 - day of month. 090000 = 9am

Is there a way I can convert that in SQL to 10/18/2008 9:00am ?

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jsuttorAsked:
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jsuttorAuthor Commented:
all of the values in Column Startdate are in this same format. Sorry if that was not clear in the original post.
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BrandonGalderisiCommented:
Here you go.

The line that leads with "set @dt = " is what you want, just replace your column name.
declare @dts varchar(20)
     ,@dt datetime
set @dts='20081018090000'
set @dt = convert(datetime, left(@dts,8), 112) + convert(datetime,substring(@dts,9,2)+':'+substring(@dts,11,2)+':'+right(@dts,2),108)
select @dt

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jsuttorAuthor Commented:
Ok well maybe I was not clear enough. I need this done in a query. I know the rest of the query. I just need to convert the values that come up in the above format to a datetime.

My query is as follows... just need the STARTDATE converted to datetime

SELECT     Name, Location, Description, StartDate
FROM         dbo.calendarEvents
ORDER BY StartDate DESC
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chapmandewCommented:
Brandon was quite clear in his explanation...just as a refresher (NO POINTS please)


select convert(datetime, left(YOURFIELDNAME,8), 112) + convert(datetime,substring(YOURFIELDNAME,9,2)+':'+substring(YOURFIELDNAME,11,2)+':'+right(YOURFIELDNAME,2),108)
FROM YOURTABLENAME
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Deepika_RastogiCommented:

Brandon is right

you just have to do this

SELECT     Name, Location, Description, (convert(datetime, left(StartDate ,8), 112) + convert(datetime,substring(StartDate ,9,2)+':'+substring(StartDate ,11,2)+':'+right(StartDate ,2),108)) as Start_Date
FROM  calendarEvents
ORDER BY Start_Date DESC

Hope this helps
Deepika
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Scott PletcherSenior DBACommented:
SELECT CONVERT(CHAR(10), CAST(LEFT(startdate, 8) AS DATETIME), 101) +
    RIGHT(CONVERT(VARCHAR(30), CAST(STUFF(SUBSTRING(startdate, 9, 4), 3, 0, ':') AS DATETIME), 0) , 8)


For example:

SELECT CONVERT(CHAR(10), CAST(LEFT(startdate, 8) AS DATETIME), 101) +
    RIGHT(CONVERT(VARCHAR(30), CAST(STUFF(SUBSTRING(startdate, 9, 4), 3, 0, ':') AS DATETIME), 0) , 8)
FROM (
    SELECT '20081018090000' AS startdate
) AS sampleData
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Scott PletcherSenior DBACommented:
[Note that format 108 will give you 24-hr time, not am/pm.]

Also, you may want to add a computed column to the table that does the conversion.  Then you won't have to repeat the code in several different SELECTs, just use a different column name when you want the formatted version.

For example:

ALTER TABLE tablename
ADD startdate_formatted AS CONVERT(CHAR(10), CAST(LEFT(startdate, 8) AS DATETIME), 101) +
    RIGHT(CONVERT(VARCHAR(30), CAST(STUFF(SUBSTRING(startdate, 9, 4), 3, 0, ':') AS DATETIME), 0) , 8)

And, from then on:

SELECT ..., startdate_formatted, ...
FROM tablename
WHERE startdate_formatted >= ...
ORDER BY startdate_formatted
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