Doomtomb
asked on
REALLY EASY I don't know why this won't enter the for loop
I keep getting compiling errors on this and I'm about ready to throw my first right through the screen of this laptop.
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main( void )
{
int quantity = 1;
int i = 1;
srand(time(NULL));
printf( "How many Quick Picks do you want?\n" );
scanf( "%d\n", &quantity );
for ( i = 1; i <= quantity i++ )
{
printf( "Quick Pick: %d\n", 1 + (rand() % 54));
}
return 0; /* program executed successfully */
}
ASKER
Jeeze, I knew it was something dumb like that. I have attached what it is right now but for some reason, it won't enter the for loop. It prints asking the user, then you type a value like 2 and enter and nothing happens.
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main( void )
{
int quantity;
int i;
srand( time( NULL ) );
printf( "How many Quick Picks do you want?\n" );
scanf( "%d\n", &quantity );
for ( i = 1; i <= quantity; i++ ) {
printf( "Quick Pick: %d\n", 1 + (rand() % 54));
}
return 0; /* program executed successfully */
}
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ASKER
Works great. My programming teacher forces us to use scanf. It sucks. I HATE THIS!!!!! I GOT SO MAD!!!!!!! THANK YOU!!!!!! *ANGRY VOICE*
note ; after quantity