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CF 3.5 System.Diagnostics.ProcessStartInfo - File Not Found

Posted on 2008-10-15
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Last Modified: 2013-11-17
Hi..
I'm using the compact framework and trying to lauch a program with the following code.
But I get file not found. The file is int he Program FIles folder
what am I doing wrong ? thanks

     System.Diagnostics.ProcessStartInfo Info = new System.Diagnostics.ProcessStartInfo();
                Info.FileName = TEST.EXE;
                Info.UseShellExecute = false;
                Info.Arguments = null;
                Info.WorkingDirectory = "\program files\myCrap\:
                System.Diagnostics.Process.Start(Info);
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Question by:JElster
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4 Comments
 
LVL 5

Expert Comment

by:jfmador
ID: 22723482
Use double \ for your path, because "\" will look for a special character like \n for new line \t for a tab space, etc.  You can also use @ before your string to prevent the compiler to translate the \ as a special charater

this :
Info.WorkingDirectory = "\\program files\\myCrap\\":
or
Info.WorkingDirectory = @"\program files\myCrap\":

instead of this
Info.WorkingDirectory = "\program files\myCrap\:
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LVL 1

Author Comment

by:JElster
ID: 22723983
Hi..
I tried those.. same issue
????
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Accepted Solution

by:
jfmador earned 400 total points
ID: 22724054
try using full path in filename instead of workingdirectory
Also add a System.IO.FileExists Condition and show the full path if file not found, be sure you didn't mistyped the file name

     System.Diagnostics.ProcessStartInfo Info = new System.Diagnostics.ProcessStartInfo();
                Info.FileName = @"\program files\mycrap\TEST.EXE";
                Info.UseShellExecute = false;
                Info.Arguments = null;

    if (System.IO.File.Exists(info.FileName))
          System.Diagnostics.Process.Start(Info);
    else
         MessageBox.Show("Unable to find : " + info.FileName);
0
 
LVL 1

Author Comment

by:JElster
ID: 22724730
If I set the filename with the path it works
If I set the working directory with just the path it does not.

???
thanks
0

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