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Datediff

How can I use sql to give me the difference between a date timestamp field in days and exclude weekends?  The data below shows how many times an item has changed status, I want to create an extra column called 'Days' to show the number of days that the item has changed status between each line.  If this item does not change status, then I want it to calculate against the current date. Please see an example of the data below:

Change Date

2008-08-13 12:16:56.377
2008-08-13 12:16:56.377
2008-08-13 19:08:39.090
2008-08-14 21:15:28.617
2008-08-24 18:57:13.433
2008-09-05 16:33:02.653
2008-09-05 16:33:02.653
2008-09-25 12:56:46.277
2008-09-30 15:42:14.880
2008-10-01 15:42:40.640
2008-10-03 15:51:36.587
2008-10-17 09:49:18.010


This is what I would like for my output to be:

Change Date                                                          Days

2008-08-13 12:16:56.377                                         0
2008-08-13 12:16:56.377                                         0
2008-08-13 19:08:39.090                                         0    
2008-08-14 21:15:28.617                                         1
2008-08-24 18:57:13.433                                        10
2008-09-05 16:33:02.653                                        12  
2008-09-05 16:33:02.653                                        12  
2008-09-25 12:56:46.277                                        20
2008-09-30 15:42:14.880                                         5
2008-10-01 15:42:40.640                                         1
2008-10-03 15:51:36.587                                         2
2008-10-17 09:49:18.010                                         14

0
daintysally
Asked:
daintysally
  • 3
1 Solution
 
momi_sabagCommented:
this will give you the result including weekends

with a as
(select change_date, row_numbeR() over (order by change_date) as rown
from your_table
)

select  t1.change_date,  
     case  when t2.rown is null then datediff(d, t1.change_date, getdate())
               else datediff(d, t1.change_date, t2.change_date)

from  a t1 left outer join a t2 on t1.rown = t2.rown-1
0
 
momi_sabagCommented:
if you want to remove the weekends you need to add in the case checks for the t1.change_date and t2.change_date day of the week and according to the dayof the week (which can be retreived using datepart) you can calculate how many weekend days you had in there
(it depends on the first day of the week and which days are considerd weekends for you)
0
 
daintysallyAuthor Commented:
I do not understand your solution.  Can you please explain further for me?
0
 
momi_sabagCommented:
the code i wrote sums up all the days
removing the weekends depends on where you from
some countries week end is friday-saturday, some weekend is saturday-sunday etc...
you need to modify the query and add logic that will calculate the number of weekend days between the dates
0
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