trying to learn sql join and having trouble...

Posted on 2008-10-19
Last Modified: 2013-12-18
Greetings all

     I bought the book "Oracle 10g:sql" and am trying to figure out SQL.  I was able to set up the books example tables I am attaching the table's schema in hopes that it helps you help me (I have a sql file that sets up these tables if that would help?).  I had some trouble reading the sqlplus output in a windows terminal window so I am now trying isql*plus.  

OK, question time...
I am having trouble with some of the queries beyond the basic stuff (like looking at a whole table, or basic join of tables, creating tables, add, drop and the like).  The examples in the book are ok but I am having trouble seeing how they translate to real world questions.  The book seems to answer questions made to show how a specific function or clause works.

for example I understand how to use min to see the oldest/newest order but all I see is the one column, how do I get the whole row or record to show?  There are 3 orders with the same date (looking at oldest) how do I get all three records to show or just one?
the error i seem to get most with this example is : not a single-group group function when I try to find a way to display more than just the oldest/newest date.  
"select customer#, min(orderdate)"

I think I understand how to join two tables but once again I am lost on how to see a useful information from that how would I see how many customers don't have an order?  I think the count function would be used but not sure how?  or what if I wanted to see a table with records (like those in customers) of customers that didn't have an order?

I have read about the functions but I guess I am not understanding their use in queries, like the avg: how would I go about finding the avg total cost of a customer's orders?

Thank you for your time and any effort put forth to help me understand.  This is my first real post here, if I have done anything wrong in my post I am sorry.  
Question by:cybercookie72
  • 3
  • 3

Author Comment

ID: 22751630
I searching through the forums here (doing my best to form a search that has something to do with my issues).  I found a post that showed me that you can nest a query and I was able to make one that I think returns the info Im looking for...the thing I was looking for was how to get more than just one column when looking for something like the oldest order date....

select * from orders
where orders.orderdate = (Select min(orders.orderdate) from orders);

now I think this returns all records where the orderdate is less than others(lowest), and this seems to return more than one record (I added and dropped records to see)

Am I on track?
LVL 20

Expert Comment

by:chaitu chaitu
ID: 22751659

this subquery gives you  minimum orderdate within orders and in the where cluase it will pass that date and will retreive that order;

Select min(orders.orderdate) from orders

Author Comment

ID: 22751980
OK, still working on trying to understand the join...
but first thank you chaituu..that query the lowest orderdate from orders, Im trying to find way to get the whole record to the query I posted..give 3 records of lowest date, I guess I cant get one record unless I use more constraints to make said record distinct from the others.

OK ...back to join stuffs.  I was joining orders and customers and when looking at each table noticed some customers do not have orders and want to count how many there are.  I am can join them and get a table with customer# that have orders

SELECT COUNT(DISTINCT customer#) "# with orders"
FROM orders JOIN customers USING(customer#);

# with orders

there are 20 customers and 21 orders, 14 customers with orders; some have multiple orders.

so how can I get some math in to the query?  how many customers do not have orders?

thanks again all
PRTG Network Monitor: Intuitive Network Monitoring

Network Monitoring is essential to ensure that computer systems and network devices are running. Use PRTG to monitor LANs, servers, websites, applications and devices, bandwidth, virtual environments, remote systems, IoT, and many more. PRTG is easy to set up & use.

LVL 20

Accepted Solution

chaitu chaitu earned 200 total points
ID: 22752002
Below query retrieves customers do not have orders.

LVL 20

Expert Comment

by:chaitu chaitu
ID: 22752004
if you find count put count(*) instead of *;anyway check with ur tables.

Author Closing Comment

ID: 31507561
Thank you for your help, your code seems to be right on.  I have not seen the EXISTS before and it took me a while to figure out what was going on.  I think I got a handle on the code you posted.  Thank you again

Featured Post

Free Tool: Port Scanner

Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I remember the day when someone asked me to create a user for an application developement. The user should be able to create views and materialized views and, so, I used the following syntax: (CODE) This way, I guessed, I would ensure that useā€¦
Checking the Alert Log in AWS RDS Oracle can be a pain through their user interface.  I made a script to download the Alert Log, look for errors, and email me the trace files.  In this article I'll describe what I did and share my script.
This video shows how to copy a database user from one database to another user DBMS_METADATA.  It also shows how to copy a user's permissions and discusses password hash differences between Oracle 10g and 11g.
Via a live example, show how to restore a database from backup after a simulated disk failure using RMAN.

861 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question