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Random Images with hyperlink to the actual corresponding product page.

Hello. What I am wanting to do is have random images rotate on my index page. I'm wanting these images to be hyperlinks to the corresponding products page. I've tried 2 different way of doing it. The first is easier for me to understand (not 100% but closer). The second I don't understand as much because the function is different. The code is like this (I added the link array at top for reffernce on the 2nd script below) but how do I change the function at the bottom to have the corresponding links with the images matched up together?

Thanks for your help!!

I have this which isn't rotating pictures but the link works:
 
function random_imglink(){
var myimages=new Array()
//specify random images below. You can have as many as you wish
myimages[1]="../new/images/cc/random_images/4719lr.jpg"
myimages[2]="../new/images/cc/random_images/6754lr.jpg"
myimages[3]="../new/images/cc/random_images/71HHGlr.jpg"
 
//specify corresponding links below
var imagelinks=new Array()
imagelinks[1]="http://www.link1.com"
imagelinks[2]="http://www.link2.com"
imagelinks[3]="http://www.link3.com"
 
var ry=Math.floor(Math.random()*myimages.length)
if (ry==0)
ry=1
document.write('<a href='+'"'+imagelinks[ry]+'"'+'><img src="'+myimages[ry]+'" border=0></a>')
}
//-->
</script>
 
##############################
Second try below
##############################
 
Or I have this which rotates images but I'm not sure how to add the link var to the function at bottom:
 
<script language="JavaScript">
<!-- Begin
 
var imagelinks=new Array()
imagelinks[1]="http://www.link1.com"
imagelinks[2]="http://www.link2.com"
imagelinks[3]="http://www.link3.com"
 
var interval = 2.5; // delay between rotating images (in seconds)
var random_display = 1; // 0 = no, 1 = yes
interval *= 1500;
 
var image_index = 0;
image_list = new Array();
image_list[image_index++] = new imageItem("../new/images/cc/random_images/4719lr.jpg");
image_list[image_index++] = new imageItem("../new/images/cc/random_images/6754lr.jpg");
image_list[image_index++] = new imageItem("../new/images/cc/random_images/71HHGlr.jpg");
 
var number_of_image = image_list.length;
function imageItem(image_location) {
this.image_item = new Image();
this.image_item.src = image_location;
}
function get_ImageItemLocation(imageObj) {
return(imageObj.image_item.src)
}
function generate(x, y) {
var range = y - x + 1;
return Math.floor(Math.random() * range) + x;
}
function getNextImage() {
if (random_display) {
image_index = generate(0, number_of_image-1);
}
else {
image_index = (image_index+1) % number_of_image;
}
var new_image = get_ImageItemLocation(image_list[image_index]);
return(new_image);
}
function rotateImage(place) {
var new_image = getNextImage();
document[place].src = new_image;
var recur_call = "rotateImage('"+place+"')";
setTimeout(recur_call, interval);
}
//  End -->
</script>

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scrathcyboy

Simply use this construction --

<A href="http://www.link1.com"><IMG src="new/images/cc/random_images/4719lr.jpg"></A>

with the link encasing the image, you cannot get dis-synchronized, and the image clicked makes the link.

Guest85

ASKER

I don't think that will work with JavaScript and random images cycling from one to another?

Guest85

ASKER

Let me elaborate a little.

The first example displays a random picture with the correct link associated with the picture. The only problem is the script doesn't automatically reload another random image without a refresh. If you hit refresh and reload the page you will get a different random image with a link.

The second example randomly changes the images on the page every 6 seconds or so. The only thing about this one is I'm not sure how to associate this function with the links and make it work. I've tried a few things but can't get it to work.

What I'm wanting is a combination of the two. I want a random picture with its corresponding link when clicked. If this image isn't clicked I want it to change or cycle from one of the random linked pictures to another.

Hope this clarified things a little. Let me know if you don't understand.

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Guest85

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Guest85

ASKER

I figured it out using the above code. Please accept as my own solution and refund points or w/e.