Solved

Random Images with hyperlink to the actual corresponding product page.

Posted on 2008-10-20
5
608 Views
Last Modified: 2009-07-15
Hello. What I am wanting to do is have random images rotate on my index page. I'm wanting these images to be hyperlinks to the corresponding products page. I've tried 2 different way of doing it. The first is easier for me to understand (not 100% but closer). The second I don't understand as much because the function is different. The code is like this (I added the link array at top for reffernce on the 2nd script below) but how do I change the function at the bottom to have the corresponding links with the images matched up together?

Thanks for your help!!

I have this which isn't rotating pictures but the link works:
 

function random_imglink(){

var myimages=new Array()

//specify random images below. You can have as many as you wish

myimages[1]="../new/images/cc/random_images/4719lr.jpg"

myimages[2]="../new/images/cc/random_images/6754lr.jpg"

myimages[3]="../new/images/cc/random_images/71HHGlr.jpg"
 

//specify corresponding links below

var imagelinks=new Array()

imagelinks[1]="http://www.link1.com"

imagelinks[2]="http://www.link2.com"

imagelinks[3]="http://www.link3.com"
 

var ry=Math.floor(Math.random()*myimages.length)

if (ry==0)

ry=1

document.write('<a href='+'"'+imagelinks[ry]+'"'+'><img src="'+myimages[ry]+'" border=0></a>')

}

//-->

</script>
 

##############################

Second try below

##############################
 

Or I have this which rotates images but I'm not sure how to add the link var to the function at bottom:
 

<script language="JavaScript">

<!-- Begin
 

var imagelinks=new Array()

imagelinks[1]="http://www.link1.com"

imagelinks[2]="http://www.link2.com"

imagelinks[3]="http://www.link3.com"
 

var interval = 2.5; // delay between rotating images (in seconds)

var random_display = 1; // 0 = no, 1 = yes

interval *= 1500;
 

var image_index = 0;

image_list = new Array();

image_list[image_index++] = new imageItem("../new/images/cc/random_images/4719lr.jpg");

image_list[image_index++] = new imageItem("../new/images/cc/random_images/6754lr.jpg");

image_list[image_index++] = new imageItem("../new/images/cc/random_images/71HHGlr.jpg");
 

var number_of_image = image_list.length;

function imageItem(image_location) {

this.image_item = new Image();

this.image_item.src = image_location;

}

function get_ImageItemLocation(imageObj) {

return(imageObj.image_item.src)

}

function generate(x, y) {

var range = y - x + 1;

return Math.floor(Math.random() * range) + x;

}

function getNextImage() {

if (random_display) {

image_index = generate(0, number_of_image-1);

}

else {

image_index = (image_index+1) % number_of_image;

}

var new_image = get_ImageItemLocation(image_list[image_index]);

return(new_image);

}

function rotateImage(place) {

var new_image = getNextImage();

document[place].src = new_image;

var recur_call = "rotateImage('"+place+"')";

setTimeout(recur_call, interval);

}

//  End -->

</script>

Open in new window

0
Comment
Question by:Guest85
  • 4
5 Comments
 
LVL 44

Expert Comment

by:scrathcyboy
Comment Utility
Simply use this construction --

<A href="http://www.link1.com"><IMG src="new/images/cc/random_images/4719lr.jpg"></A>

with the link encasing the image, you cannot get dis-synchronized, and the image clicked makes the link.
0
 
LVL 1

Author Comment

by:Guest85
Comment Utility
I don't think that will work with JavaScript and random images cycling from one to another?
0
 
LVL 1

Author Comment

by:Guest85
Comment Utility
Let me elaborate a little.

The first example displays a random picture with the correct link associated with the picture. The only problem is the script doesn't automatically reload another random image without a refresh. If you hit refresh and reload the page you will get a different random image with a link.

The second example randomly changes the images on the page every 6 seconds or so. The only thing about this one is I'm not sure how to associate this function with the links and make it work. I've tried a few things but can't get it to work.

What I'm wanting is a combination of the two. I want a random picture with its corresponding link when clicked. If this image isn't clicked I want it to change or cycle from one of the random linked pictures to another.

Hope this clarified things a little. Let me know if you don't understand.
0
 
LVL 1

Accepted Solution

by:
Guest85 earned 0 total points
Comment Utility
Got the links working other than the images are no longer random. They appear in a ordered list/sequence one after another. Any help on implementing the images to a random sequence

   <script type="text/javascript">

     rotating_images = new Array();
 

	  rotating_images.push(new RotatingImage('../new/images/cc/random_images/pic1.jpg','http://www.link1.com'));

      rotating_images.push(new RotatingImage('../new/images/cc/random_images/pic2.jpg','http://www.link2.com'));

      rotating_images.push(new RotatingImage('../new/images/cc/random_images/pic3.jpg','http://www.link3.com'));
 

      var active_image_delay = 3; //in seconds
 

      var active_image_index = 0;
 

      function rotateImages() {
 

        if (!document.getElementById('my_images') || rotating_images.length < 1) return;

        var new_image_code = '';
 

        new_image = document.createElement('IMG');

        new_image.src = rotating_images[active_image_index].image;

        new_image.border = "0";
 

        new_link = document.createElement('A');

        new_link.href = rotating_images[active_image_index].url;
 

        new_link.appendChild(new_image);
 

        if (document.getElementById('my_images').hasChildNodes() ) {

          while (document.getElementById('my_images').childNodes.length >= 1 ) {

            document.getElementById('my_images').removeChild(document.getElementById('my_images').firstChild );

          }

        }
 

        document.getElementById('my_images').appendChild(new_link);
 

        active_image_index = (active_image_index+1)%rotating_images.length;
 

        setTimeout('rotateImages();',active_image_delay*1000);

      }      

	  function RotatingImage (image_url, url) {

        this.image = image_url;

        this.url = url;

      }

	</script>

---------------------

<body onLoad="rotateImages();">

<div id="my_images" align="center"></div>

Open in new window

0
 
LVL 1

Author Comment

by:Guest85
Comment Utility
I figured it out using the above code. Please accept as my own solution and refund points or w/e.
0

Featured Post

Highfive Gives IT Their Time Back

Highfive is so simple that setting up every meeting room takes just minutes and every employee will be able to start or join a call from any room with ease. Never be called into a meeting just to get it started again. This is how video conferencing should work!

Join & Write a Comment

Suggested Solutions

Title # Comments Views Activity
Need to learn promise API 2 27
Condidional <a href = ....> 1 23
Python On Mouseover Save URL/Link 4 29
Re-position the objects 7 46
Having worked on larger scale sites, we found out that you are bound to look at more scalable solutions to integrating widgets, code snippets or complete applications and mesh them into functional sites, in any given composition. To share some of…
This article discusses how to create an extensible mechanism for linked drop downs.
The viewer will learn the basics of jQuery, including how to invoke it on a web page. Reference your jQuery libraries: (CODE) Include your new external js/jQuery file: (CODE) Write your first lines of code to setup your site for jQuery.: (CODE)
The viewer will learn the basics of jQuery including how to code hide show and toggles. Reference your jQuery libraries: (CODE) Include your new external js/jQuery file: (CODE) Write your first lines of code to setup your site for jQuery…

771 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

10 Experts available now in Live!

Get 1:1 Help Now